Answer:
. The loop is pushed to the right, away from the magnetic field
Explanation
This decrease in magnetic strength causes an opposing force that pushes the loop away from the field
Answer:

Explanation:
Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

Due to the definition of cross product, the magnitude of the torque is given by:

Where
is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when
is equal to one, solving for r:

The hoop is attached.
Consider that the friction force is given by:
F = μ·N
= μ·m·g·cosθ
We also know, considering the forces of the whole system, that:
F = -m·a + m·g·sinθ
and
a = (1/2)·<span>g·sinθ
Therefore:
</span>-(1/2)·m·g·sinθ + m·g·sinθ = <span>μ·m·g·cosθ
</span>(1/2)·m·g·sinθ = <span>μ·m·g·cosθ
</span>μ = (1/2)·m·g·sinθ / <span>m·g·cosθ
= </span>(1/2)·tanθ
Now, solve for θ:
θ = tan⁻¹(2·μ)
= tan⁻¹(2·0.9)
= 61°
Therefore, the maximum angle <span>you could ride down without worrying about skidding is
61°.</span>
Answer:
a) V_a = -5.7536 10⁺⁷ V
, b) Vb = -1.92 10⁻⁷ V c) the sign of the potential change
Explanation:
The electrical potential for a point charge
V = k q / r
Where k is the Coulomb constant that you are worth 8.99 10⁹ N m² / C²
a) potential At point x = 0.250 cm = 0.250 10-2m
V_a = -8.99 10⁹ 1.6 10⁻¹⁹ /0.250 10⁻²
V_a = -5.7536 10⁺⁷ V
b) point x = 0.750 cm = 0.750 10-2
Vb = 8.99 10⁹ (-1.6 10⁻¹⁹) /0.750 10⁻²
Vb = -1.92 10⁻⁷ V
potemcial difference
ΔV = Vb- Va
V_ba = (-5.7536 + 1.92) 10⁻⁷
V_ba = -3.83 10⁻⁷ V
c) To know what would happen to a particle, let's use the relationship between the potential and the electric field
ΔV = E d
The force on the particle is
F = q₀ E
F = q₀ ΔV / d
We see that the force on the particle depends on the sign of the burden of proof. Now the burden of proof is negative to pass between the two points you have to reverse the sign of the potential, bone that the value should be reversed
V_ba = 0.83 10⁻⁷ V