You're looking for the extreme values of 
subject to the constraint 
.
The target function has partial derivatives (set equal to 0)
so there is only one critical point at 
. But this point does not fall in the region . There are no extreme values in the region of interest, so we check the boundary.
Parameterize the boundary of by
with 
. Then 
can be considered a function of 
alone:
has critical points where 
:
but 
for all , so this case yields nothing important.
At these critical points, we have temperatures of
so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.
Water was pumped out in t-hours.
Time t would be the domain, 0 to t.
Answer:
Step-by-step explanation: please go through the attached file for detailed explanation .
The following are the choices on this question:
A.6
B. 39
C. 26
D. 12
The answer is option D. 12.
Check this out:
S=n² + n
S= 12² + 12
(you can get the square of 12 by multiplying 12 by itself: 12 × 12)
S=144 +12
S=156
Answer:
y = x^2 -6x -27
Step-by-step explanation:
When "a" is a root, (x-a) is a factor. The minimum polynomial with the listed roots will be ...
y = (x -9)(x +3)
y = x^2 -6x -27
