Two brothers walk toward each other from a starting distance

Drag each expression to show whether it is equivalent to

Kazeer [188]

Answer:

We need to find which expressions are equivalent to $6(c+6)$ , $6c+6$ or neither.

$6c+12$ : We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

$6c+12=+(c+2)$

Therefore, this expression is equivalent to neither of the given expressions.

$2(3c+3)$ : We just need to apply the distributive property.

$2(3c+3)=6c+6$

Therefore, this expression is equivalen to $6c+6$ .

We use the same process to the other expressions.

$(6c)+(6\times 6)=6c+36=6(c+6)$

$3c+6+3c=6c+6$

$6c+36=6(c+6)$

$(6+c)+(6+6)=c+18$ , equivalent to neither.

7 0

2 years ago

Solve this questions with steps

Alex_Xolod [135]

Provide better info thanks

4 0

2 years ago

Which equation can be used to represent "three minus the difference of a number and one equals one-half of the difference of thr

Rina8888 [55]

Answer:

3 - (n - 1) = 1/2(3n - 4)

Step-by-step explanation:

We want to write three minus the difference of a number and one equals one-half of the difference of three times the same number and four as an equation.

Let the number be n.

The first part is: three minus the difference of a number and one:

3 - (n - 1)

The second part is: one-half of the difference of three times the same number and four:

1/2(3n - 4)

Now, let us equate the first and second parts:

3 - (n - 1) = 1/2(3n - 4)

PS: I really do not understand the options

9 0

2 years ago

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Evaluate. 58−(14)2=58-142= ________

nasty-shy [4]

For this case we have the following expression:

$58- (14) ^ 2$

The first step is to solve the quadratic term.

We have then:

$58- (14) ^ 2 = 58-196$

Then, the second step is to subtract both resulting numbers:

$58- (14) ^ 2 = -138$

We observe that the result obtained is a negative number.

Answer:

The result of the expression is given by:

$58- (14) ^ 2 = -138$

7 0

2 years ago

Cones A and B both have volume cubic 48π units, but have different dimensions. Cone A has radius 6 units and height 4 units. Fin

kogti [31]

Answer:

r = 2 units

h= 36 units

Step-by-step explanation:

Given That:

Cones A and B both have volume cubic 48π units

The volume of a cone = $\frac{1}{3} \pi r^2h$

So for cone A

$V_A = \frac{1}{3} \pi r_A^2 h_A$

Volume for cone B

$V_B = \frac{1}{3} \pi r_B^2 h_B$

Due to different dimensions;

Cone A has

radius = 6 units

height = 4 units

To determine the one possible radius and height for cone B;

we have

$\frac{1}{3} \pi r_A^2 h_A =\frac{1}{3} \pi r_B^2 h_B$

$\frac{1}{3} \pi (6)^2 (4) =\frac{1}{3} \pi r_B^2 h_B$

$150.9=\frac{1}{3} \pi r_B^2 h_B$

$150.9=1.047r_B^2 h_B$

$r_B^2 h_B=144.12$

$r_B^2 h_B=144$

Therefore; the only possible way for this equation is :

$r_B = (2)\\h_B = 36$

If we are to check: we will realize that;

$r_B^2h_B = (2)^2*36 =144$

Therefore, the possible radius for the cone B = 2 units and height = 36 units. Hence from the question, we are told they both have the same volume of 48 π units.

7 0

2 years ago

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