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2 years ago

Paul rolls a fair dice 174 times. How many times would Paul expect to roll a number greater than 2?

Mathematics

1 answer:

Harman [31]2 years ago

4 0

Answer:

116 times

Step-by-step explanation:

A fair dice has 6 faces: 1, 2, 3, 4, 5, 6

The probability of rolling a number greater than 2( face of 3, 4, 5, 6 - 4 elements in total) is:

P = number of selected elements/total number of elements

P = 4/6

P = 2/3

=> Paul rolls a fair dice 174 times, Paul will expect the number of times that a number greater than 2 is rolled:

N = 174 x (2/3) = 116

Hope this helps!

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