If Ray QS bisects angle PQR , m of angle PQS=7x-6 and m of angle SQR =4x+15,find m of angle PQT
1 answer:
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The equation is:
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8) / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)
t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8) / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)
t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.
Answer:
a. Yes(n=500>=5, n(1-p)=25>=5)
b. 0.15241
Step-by-step explanation:
a. A normal approximation to the binomial can be used 5 and n(1-p)>=5:
#We calculate our p as follows:
=x/n=470/500=0.94
n=500
n(1-p)=500(1-0.95)=25
Hence, we can use the normal approximation.
b. This is a normal approximation.
-Given that p=0.95(95%)
-We verify if our distribution can be approximated to a normal:
Hence, we can use the normal approximation of the form:
Hence, the probability of the sample proportion is the same as the proportion of the sample found is 0.15241