Answer:
H0: The new cancer drug increases the mean survival time by 30 days
Ha: The new cancer drug increases the mean survival time by 30 or more than 30 days.
If fail to reject H0 (the null hypothesis), the conclusion is that the new cancer drug increases the mean survival time by 30 days.
Step-by-step explanation:
The null hypothesis is a statement from a population parameter which is either rejected or accepted (fail to reject) upon testing. It is expressed using the equality sign.
The alternate hypothesis is also a statement from a population parameter which negates the null hypothesis and is accepted if the null hypothesis is rejected. It is expressed using any of the inequality signs.
The test is a two-tailed test because the alternate hypothesis is expressed using more than or equal to.
If I fail to reject H0, it means the test statistic falls within the region bounded by the critical values.
It would therefore be concluded that the new cancer drug increases the mean survival time by 30 days.
Answer:

And when we apply the limit we got that:

Step-by-step explanation:
Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"
We have the following formula in order to find the sum of cubes:

We can express this formula like this:
![\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7Di%5E3%20%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5B%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5E2)
And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2
![\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5B%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5E2)
If we operate and we take out the 1/4 as a factor we got this:

We can cancel
and we got

We can reorder the terms like this:

We can do some algebra and we got:

We can solve the square and we got:

And when we apply the limit we got that:

They are comparing the number of cats in teh shelter to the number of dogs in the shelter.
2(5x + 2)^2 = 48
divide both sides by 2
(5x + 2)^2 = 24
square root both sides to clear the power of two.
5x + 2 = + - sqrt24
subtract 2 from both sides
5x = -2 + - sqrt 24
divide both sides by 5
x = (-2 +-sqrt24)/5 or decimal answers .58 and -1.38
Given maria has
in the pennies & quarters.
she has twice as many pennies as quarters.
find out the coins
let us assume the quarters are x
than the pennies are 2x.
Formula
value of the pennies + value of the quarters = total value of coins
1 quarters =$ 0.25
1 pennies = $0.01
Thus
0.25x + 0.01 (2x) = 2.43
0.27 x = 2.43
x = 9
2x = 18
i.e the number of quarters are 9 and the number of pennies are 18.
Hence proved