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Juliette [100K]
2 years ago
13

Triangles R S T and V U T are connected at point T. Angles R S T and V U T are right angles. The length of side R S is 12 and th

e length of side S T is 16. The length of side T U is 8 and the length of U V is 6. Which statements can be concluded from the diagram and used to prove that the triangles are similar by the SAS similarity theorem? StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction = StartFraction R T Over V T EndFraction StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction and angle S is-congruent-to angle U StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction = StartFraction R T Over V T EndFraction

Mathematics
2 answers:
nydimaria [60]2 years ago
8 0

Answer:

A

Step-by-step explanation:

I took the test

il63 [147K]2 years ago
6 0

Answer:

StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U

Step-by-step explanation:

The expression below means RS/VU = ST/UT

See the attachment for better explanation.

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A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower costs $329.99. If 30
Annette [7]

19 small mowers and 11 large mowers are sold

<em><u>Solution:</u></em>

Let "a" be the number of small mowers sold

Let "b" be the number of large mowers sold

Cost of each small mower = $ 249.99

Cost of each large mower = $ 329.99

<em><u>30 total mowers were sold</u></em>

Therefore,

a + b = 30

a = 30 - b ------------- eqn 1

<em><u>The total sales for a given year was $8379.70</u></em>

<em><u>Thus we frame a equation as:</u></em>

number of small mowers sold x Cost of each small mower + number of large mowers sold x Cost of each large mower = 8379.70

a \times 249.99 + b \times 329.99 = 8379.70

249.99a + 329.99b = 8379.70 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

249.99(30 - b) + 329.99b = 8379.70

7499.7 - 249.99b + 329.99b = 8379.70

80b = 8379.70 - 7499.7

80b = 880

Divide both sides by 80

b = 11

<em><u>Substitute b = 11 in eqn 1</u></em>

a = 30 - 11

a = 19

Thus 19 small mowers and 11 large mowers are sold

8 0
2 years ago
Tasha has eight more fish than Oscar, who has twice as many fish as Cecilia. If altogether they have 148 fish, how many fish do
Viefleur [7K]

Answer:

They each have 64

Step-by-step explanation:

let C = number of fish that Cecilia has --- then, O = 2C, where O = number of fish that Oscar has --- and T = O + 8 = 2C + 8, where T = number of fish that Tasha has --- then, C + O + T = C + 2C + (2C + 8) = 148 --- or, 5C + 8 = 148 --- or, 5C = 140 --- or, C = 140/5 = 28 --- and, O = 2C = 2(28) = 56 --- and, T = O + 8 = 56 + 8 = 64

7 0
2 years ago
Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well
laiz [17]

Answer:

The  value is  P(A) =  0.133617

Step-by-step explanation:

From the question we are told that

  The  mean is  \mu =  7.5

  The standard deviation is  \sigma  =  0.2

  The safest water level is  between  7.2 and  7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

       P(A) =  1 - P(7.2 \le X  \le 7.8 )

Here  

      P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } <  \frac{X - \mu }{ \sigma }

Generally \frac{X - \mu }{ \sigma } =  Z (The  \ standardized \  value  \  of  X )

So

 P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z    

 P(7.2 < X  < 7.8 ) = P(-1.5 < Z  

=>  P(7.2 < X  < 7.8 ) = P(Z <  1.5) - P(  Z < - 1.5)

From the z-table the probability of  (Z <  -1.5) and   (  Z <1.5)  are

    P(Z <  1.5) =  0.93319

and  

    P(Z <  -1.5) =  0.066807

So

      P(7.2 < X  < 7.8 ) =0.93319 - 0.066807

       P(7.2 < X  < 7.8 ) =0.0866383

So

   P(A) =  1 - 0.0866383

=>  P(A) =  0.133617

5 0
1 year ago
A 12-centimeter rod is held between a flashlight and a wall as shown. Find the length of the shadow on
choli [55]

Answer:

48 cm

Step-by-step explanation:

Given:

Distance of rod from the wall = 45 cm

Distance of rod from the light = 15 cm

Length of rod = 12 cm

We can see that <DAM and <BAF are equal

Also, <DMA and <BFM are equal because they are corresponding angles

To find the length of the shadow, let's take the equation

\frac{DM}{BF} = \frac{AM}{A.F}

Where.:

DM = ½ of length of the rod = ½*12 = 6

A.F = 15 + 45 = 60 cm

AM = 15 cm

Therefore,

\frac{DM}{BF} = \frac{AM}{A.F}

= \frac{6}{BF} = \frac{15}{60}

Cross multiplying, we have:

15 * B.F = 60 * 6

15 * B.F = 360

BF = \frac{360}{15}

BF = 24 cm

The shadow on the wall =

2 * BF

= 2 * 24

= 48 cm

The shadow on the wall is 48 cm

7 0
1 year ago
The number 8.64E9 appears on a calculator. In standard notation, this number is
Lunna [17]
Here are all of your answers:

1) 8,640,000,000
2) 864,000,000,000,000
3) 864,000,000,000
4) 86,400,000,000,000

I hope this helps! If it does, please rate as Brainliest :D
6 0
2 years ago
Read 2 more answers
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