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artcher [175]
2 years ago
15

A vehicle with a particular defect in its emission control system is taken to a succession of randomly selected mechanics until

r = 15 of them have correctly diagnosed the problem. Suppose that this requires diagnoses by 20 different mechanics (so there were 5 incorrect diagnoses). Let p = P(correct diagnosis), so p is the proportion of all mechanics who would correctly diagnose the problem. What is the mle of p?

Mathematics
1 answer:
IrinaK [193]2 years ago
3 0

Answer:

the mle of P=0.833

Step-by-step explanation:

X=incorrect answer

And probability of success to be denoted as P

Here X posses a binomial distribution along with 'r' and 'p'parameter

CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION

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A triangular playground is to be enclosed using two pieces of fencing and the wall of a building. The wall of the building is 14
Greeley [361]

Answer:

12

Step-by-step explanation:

hope this helps

5 0
2 years ago
A 2-column table with 6 rows. The first column is labeled miles driven with entries 27, 65, 83, 109, 142, 175. The second column
Helen [10]

Answer:

1) The linear regression model is y = -0.0348·x + 13.989

2) The correlation coefficient is -0.0725

3) The strength of the model is strong - association

Step-by-step explanation:

1)

                         X            Y          XY       X²

                         27            13           351          729

                         65             12          780         4225

                         83              11          913         6889

                         109            10          1090      11881

                         142            9            1278     20164

                         175              8           1400      30625

                ∑      601              63 5812 74513

From y = ax + b, we have

a = \frac{n\sum xy - \sum x\sum y }{n\sum x^{2}-\left (\sum x  \right )^{2}} = \frac{6 \times 5812  - 601 \times 63}{6 \times 74513-601^{2}} = - 0.0348

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989

Therefore, the linear regression model is y = -0.0348·x + 13.989

2)

r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x  \right )^{2}] [n\sum y^{2}-\left (\sum y  \right )^{2}]}}  = \frac{6 \times 5812  - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6  \times 3969 - 63^2]} } = - 0.0725

3) The strength is - association.

5 0
2 years ago
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Answer:

11

Step-by-step explanation:

4=1

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Multiply this by 9:

275/32 x 9 = 77.34375 in^2

You can round the value accordingly.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

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antiseptic1488 [7]

Answer:

its not showing up

Step-by-step explanation:

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