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2 years ago

Solve StartFraction one-third over 5 endFraction = StartFraction a over 20 EndFraction

Mathematics

2 answers:

Anestetic [448]2 years ago

6 0

Answer:

4/3

Step-by-step explanation:

i did it

MrRa [10]2 years ago

4 0

Answer:

I think it is 4/3! I got this on edgenuity.

Hopes this helps you on whatever website or test you have!

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Adrian Beltre hit 48 home runs during the 2004 Major League Baseball season, but only hit 19 home runs in the 2005 season. By wh

aliya0001 [1]

Answer:

60.42%

Step-by-step explanation:

Number of home runs hit by Adrian Beltre in 2004 = 48

Number of home runs hit by Adrian Beltre in 2005 = 19

To find:

Percentage decrease in home run production from 2004 to 2005.

Solution:

To find the percentage decrease, first of all we need to find the decrease in the number of home runs and then we will divide with the number of home runs in 2004 and then finally will multiply the result with 100 to get the percentage decrease.

Decrease in the number of home runs = Number of home runs in 2004 - Number of home runs in 2005 = 48 - 19 = 29

$\text{Percentage of decrease in Home runs} = \dfrac{\text{Decrease in home runs}}{\text{Number of home runs in 2004}}\times 100\\\Rightarrow \text{Percentage of decrease in Home runs} = \dfrac{29}{48}\times 100 \approx \bold{60.42\%}$

Therefore, by 60.42% Beltre's home run production has decreased from 2004 to 2005.

4 0

2 years ago

If AB is parallel to CD and the slope of CD is -5, what sis the slope of AB?

Lady bird [3.3K]

Answer:

The answer is D. -5

Step-by-step explanation:

Since AB is parallel to CD, their slopes are the same. Parallel actually means to have the same slope.

7 0

2 years ago

Read 2 more answers

Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when

valentina_108 [34]

Solution:

$f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$

We have to find the remainder when f(x) is divided by $x^2-1.$

x²-1=0

x= $\pm1$

$f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13$

So, remainder is 13 and -13.

5 0

2 years ago

Read 2 more answers

Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b

horrorfan [7]

Answer:

a. $X\sim N(\mu = 6.1, \sigma = 1.9)$ b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is $z_{1} = (6.4-6.1)/1.9 = 0.1579$ and the z-score related to 7 kg is $z_{2} = (7-6.1)/1.9 = 0.4737$ , we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0

2 years ago

Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr

Gala2k [10]

Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Parallelogram ABCD:

A(2,5)

B(5,4)

C(5,2)

D(2,3)

Parallelogram A'B'C'D':

A'(5,-4)

B'(4,-5)

C'(2,-5)

D'(3,-2)

Rule:

A(2,5)→A'(5,-2)

B(5,4)→B'(4,-5)

C(5,2)→C'(2,-5)

D(2,3)→D'(3,-2)

so the rule is

(x,y)→(y,-x)

4 0

2 years ago

Read 2 more answers