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2 years ago

7

Which of the following is equivalent to RootIndex 5 StartRoot 13 cubed EndRoot? 132 1315 13 Superscript five-thirds 13 Superscri

pt three-fifths

1 answer:

worty [1.4K]2 years ago

7 0

Answer:

c on ed

Step-by-step explanation:

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Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o

AlekseyPX

Answer : 96

x – y = 16 --------> equation 1

$\frac{1}{8} x +\frac{1}{2} y = 52$

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

$\frac{1}{8} x +\frac{1}{2} ( -16 + x ) = 52$

$\frac{1}{8} x - 8 + \frac{1}{2} x = 52$

$\frac{1}{8} x + \frac{1}{2} x - 8 = 52$

Take common denominator to combine fractions

$\frac{1}{8} x + \frac{4}{8} x -8 = 52$

$\frac{5}{8} x - 8 = 52$

Add 8 on both sides

$\frac{5}{8} x = 60$

Multiply both sides by $\frac{8}{5}$

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

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2 years ago

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The table gives the highest and lowest recorded temperatures for six cities. Which cities recorded a difference between their hi

S_A_V [24]

Answer:

A and E

Step-by-step explanation:

Death Valley and Alaska

73+42=115

134+15=149

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2 years ago

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Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

So

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

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2 years ago

Todd had 6 gallons of gasoline in his motorbike. After driving 150 miles, he had 3 gallons left. Compute the slope, or rate of

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So for every gallon he can drive 50 miles. So I think the slope would be 50/-1

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What is the common ratio of the geometric sequence whose second and fourth terms are 6 and 54, respectively?

Gnom [1K]

The common ratio is 3.

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2 years ago

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