Triangle J L N is cut by line segment K M. LIne segment K M goes from side J L to side L N. The length of J K is 10, the length
1 answer:
Answer:
D. Yes, because StartFraction 16 Over 10 EndFraction equals StartFraction 24 Over 15 EndFraction.
Step-by-step explanation:
When two line are parallel, they do not meet even with continuous extension of their length.
In the given triangle JLN, line segment KM would be parallel to side JN if;
=
Given that: KL = 16, JK = 10, LM = 24 and MN = 15.
⇒ =
=
Therefore, since the ratios are the same then KM ∥ JN. So that the statement; Yes, because equals
is correct.
You might be interested in
Answer:
11.51% probability that the mean annual salary of the sample is between $71000 and $73500
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
What is the probability that the mean annual salary of the sample is between $71000 and $73500?
This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So
X = 73500
By the Central Limit Theorem
has a pvalue of 0.1151
X = 71000
has a pvalue of 0.
0.1151 - 0 = 0.1151
11.51% probability that the mean annual salary of the sample is between $71000 and $73500