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Sveta_85 [38]
2 years ago
3

A blanking operation is to be performed on 2.0 mm thick cold rolled steel (half hard). The part is circular with diameter = 75.0

mm. Determine the appropriate punch and die sizes for this operation.
Engineering
1 answer:
Musya8 [376]2 years ago
7 0

Answer:

The punch size is 74.70 mm

The die size is 75 mm

Explanation:

From the table of allowance, the allowance for cold rolled steel (A_c) is given as 0.075.

Given that: thickness = 2.00 mm, blank diameter (D_b)= 75.0 mm

The clearance (c) is the product of allowance and the thickness of the cold rolled steel. It is given by:

c=thickness*A_c=2\ mm(0.075)=0.15\ mm

The die diameter is equal to the blank diameter and the punch diameter is smaller than the blank diameter by twice the clearance

Punch diameter = D_b-2c=75\ mm-2(0.15)=75\ mm-0.3\ mm = 74.70\ mm

Die diameter = D_b=75\ mm

the appropriate punch diameter is 74.70 mm and die size is 75 mm

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