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zalisa [80]
1 year ago
13

Which statement best supports the argument that

Biology
1 answer:
Nadya [2.5K]1 year ago
7 0

Answer:

C) a carbohydrate that takes longer to break down in the body puts less sugar into your bloodstream

Explanation:

Whole grains are a more complex carbohydrate than your basic white bread, meaning it takes longer to break down and doesn't flood your bloodstream with sugar the way white bread does when eaten. (also, the other three are not very closely related to/answer the question)

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Over time, the movement of people on Earth has steadily increased. This has altered the course of human evolution by increasing
Yuliya22 [10]

Answer:

3

Explanation:

4 0
2 years ago
Based on the results above, you study the settlement patterns of the three species. You establish transects on each of your expe
dem82 [27]

Answer:

c. Physical adaptations to the environment drive the distribution of all three species in the wild.

Explanation:

Options A and B refer to competition between species. The experiment was about the colonizing ability of the three species, and not the interaction among them. So these two options are not correct.

Option D states that species A is better adapted to the upper intertidal zone than the middle or lower. But the table shows that species A is equally adapted to colonize upper and middle intertidal zone, and less adapted to colonize lower zones.

The correct option is C. When these competing species coexist, this is because of niche partitioning or niche differentiation. If there is not any differentiation between them, the dominant species displaces the weak species. In the exposed example,  the three species coexist in the middle and lower zones, which means that they probably have different niches and got adapted to living to their environments. This adaptation to different conditions is what leads to their distribution.    

In the exposed example, species A and B can live in the upper intertidal zone, where species C can not live because they can not tolerate environmental conditions. The three species can live in the middle zone, but still, A and B are more adapted to this area than C. Among A and B, B is the most adapted to living in the upper and middle zones. Species C seems to be very adapted to live in the lower intertidal zone, where species A and B can also live, but are less adapted to this area, probably due to environmental conditions or due to their vulnerability to predation. In this last area, species A is less adapted.

   

3 0
2 years ago
You complete an experiment measuring the spread of the Cordyceps fungus across a forest environment. You measure the amount of g
anygoal [31]

This seems to be the best answer: C. The data does not take into account underground growth and the actual area of fungus spread may be larger, so the original conclusion of the experiment is not accurate.

8 0
1 year ago
Read 2 more answers
The major structural difference between chromatin and chromosomes is that the latter are
labwork [276]

Answer:

The major structural difference between chromatin and chromosomes is that the latter are more organized and condensed.

Explanation:

Chromatin is genetic material packaged into a complex by special proteins (histones). That complex is in the form of uncoiled structures, so chromatin fibers are long and thin. Chromatin structure is permissive to DNA replication, transcription and recombination events.

On the other hand, chromosomes are highly condensed structures of genetic material that are formed just before the cell division.

5 0
2 years ago
kmf Of the 40 specimens of bacteria in a dish,3 specimens have a certain trait. If 5 specimens are to be selected from the dish
almond37 [142]

Answer:

\frac{C^{3}_1* C^{47}_4}{C^{40}_5}

Explanation:

It is given that out of 40, total 5 specimen are selected.

Thus, the number of ways in which 5 specimens are selected from a given sample of 40 is given by

C^{40}_{5}\\

Number of specimen with certain trait is equal to 3.

Now, total 5 specimen are selected out of which one specimen is selected from the set of specimen that has certain trait (i.e out of 3) while the remaining four specimen will be selected from the rest 40-3=37 specimen.

Thus, the probability of choosing only 1 of the 5 specimens with the trait is equal to

\frac{C^{3}_1* C^{37}_4}{C^{40}_5}

7 0
1 year ago
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