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anyanavicka [17]
2 years ago
3

Anne, Becky and Charlotte had sums of money in the ratio 7:6:5. One of them gave £9 to one of the others and this changed the ra

tio (in the same order of names) to 6:5:4. The total sum of money remained the same; what was it?
Mathematics
1 answer:
Luda [366]2 years ago
3 0

Answer:

The total sum of money is £810

Step-by-step explanation:

The parameters given are;

The ratio of the sum Anne, Becky and Charlotte had = 7:6:5

One of them gave one of the others £9 and the new ratio becomes 6:5:4

The total sum of money remains the same = M

The initial fraction amount of the total sum of money each had is given as follows;

Anne = 7/(7 + 6 + 5)×M = 7/18·M = 0.389·M

Becky = 6/18·m = 1/3·M

Charlotte = 5/18·M = 0.278·M

After one of them gave £9 to one of the others, the fraction amount of the total sum of money each had became;

Anne = 6/(6 + 5 + 4)×M = 6/15·M = 0.4·M

Becky = 5/15·m = 1/3·M

Charlotte = 4/15·M = 0.267·M

Therefore, given that Anne's fraction of the total sum of money increased while Charlotte's fraction of the total sum of money decreased, it was Charlotte that gave Anne £9

Therefore, the fraction of the total sum of money equivalent to £9 is found s follows;

5/18·M - 4/15·M = 1/90·M = £9

Therefore;

M = 90 × £9 = £810

The total sum of money = £810.

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It is 1 1/4 miles from Ahmed’s house to school. How far does Ahmed’s travel in 5 days walking to school and back
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Ahmed travel 12\frac{1}{2} miles in 5 days walking to school and back.

Step-by-step explanation:

Distance from house to school = 1\frac{1}{4} miles

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Total distance in 1 day = 1\frac{1}{4}+1\frac{1}{4}=\frac{5}{4}+\frac{5}{4}

Total distance in 1 day = \frac{5+5}{4}=\frac{10}{4}

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Keywords: fraction, addition

Learn more about fractions at:

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<span>
</span>

<span>Going back to the calculation for the ratio,
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