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2 years ago

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The expression x−y equals 0.7 if x and y have certain values. Evaluate the following expressions with the same values of x and y

. What is y−x?

1 answer:

lisov135 [29]2 years ago

3 0

Answer:

-0.7

Step-by-step explanation:

$x-y=0.7$

You can choose any digits you wish for $x$ and $y$ but the difference must be 0.7. I chose 1.0 and 0.3.

$x=1\\y=0.3\\x-y=0.7\\\\y-x=\\0.3-1=\\-0.7$

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What number is represented by 4x²+17x+2 if x=10?

Fynjy0 [20]

Answer:

at x = 10, $4x^{2} + 17x + 2 = 572$

Step-by-step explanation:

The given equation is $4x^{2} + 17x + 2$

Here, lets substitute the value of x = 10

So, the equation simplifies to ,

$4 \times (10)^{2} + 17(10) + 2$

= (4 x 100) + 170 + 2 = 400 + 170 + 2

= 572

So, at x = 10, $4x^{2} + 17x + 2 = 572$

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2 years ago

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Answer:

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Step-by-step explanation:

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If a walnut costs 20 cents, he can buy 3.

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2 years ago

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2 years ago

Read 2 more answers

g An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the

blagie [28]

Answer:

A 90% confidence interval of the true mean is [$119.86, $123.34].

Step-by-step explanation:

We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.

Also, the standard deviation of the population was $6.36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean amount of money spent on textbooks = $121.60

$\sigma$ = population standard deviation = $6.36

n = sample of students = 36

$\mu$ = population mean

<em>Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.</em>

<em />

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $121.60-1.645 \times {\frac{6.36}{\sqrt{36} } }$ , $121.60+1.645 \times {\frac{6.36}{\sqrt{36} } }$ ]

= [$119.86, $123.34]

Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].

5 0

2 years ago

Find the volume of a right circular cone that has a height of 12.7 m and a base with a circumference of 18.9 m. Round your answe

DochEvi [55]

Step-by-step explanation:

We have,

Height of cone, h = 12.7 m

Circumference of base, C = 18.9 m

The base of a circular cone is circular. The circumference of circle is given by :

$C=2\pi r$

r is radius

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{18.9 }{2\pi}\\\\r=3\ m$

The volume of a right circular cone is given by the formula as :

$V=\dfrac{1}{3}\pi r^2h$

$V=\dfrac{1}{3}\times 3.14 \times 3^2\times 12.7\\\\V=119.634\ m^3$

7 0

2 years ago