All categories

2 years ago

If James grows by 20 inches everyday starting

1 answer:

5 0

Okay so if James grows 20 inches everyday between Monday and Wednesday that is 3 days (Monday, Tuesday, Wednesday). When it asks for the difference it is asking for how many inches he grew in total. So let’s call the “difference” Y.
The equation would be...
3 x 20 = Y
60 = Y
Therefore, the answer would be 60 inches.

You might be interested in

shanti wrote the predicted values for a data set using the line of best fit y = 2.55x – 3.15. she computed two of the residual v

Delvig [45]

The question asks us to determine the values for a and b in the linear equation. Linear equation in the slope-intercept form is : y = a x + b. This equation is: y = 2.25 x - 3.15. The slope: a = 2.25 and the y-intercept is: b = -3.15. Answer: a = 2.25 and b = - 3.15.

8 0

2 years ago

Read 2 more answers

A decimal number changed to 23.7 after it was rounded. Give a decimal number that is less than 23.7 and another that is greater

mrs_skeptik [129]

Two possible answers are:

23.65 and 23.72.

Explanation:

For the first number, 23.65, we are rounding to the tenths place. 23.65 itself is smaller than 23.7. Looking behind the tenths place, the digit behind it is 5. This means we round the tenths place up; this becomes 23.7.

23.72 is larger than 23.7. We will round it to the tenths place as well. Looking behind the tenths place, we have a 2; this means we "round down." This means leave the 7 as it is and drop the other digits behind it. This gives us 23.7.

3 0

2 years ago

Read 2 more answers

Henri has $24,000 invested in stocks and bonds. The amount in stocks is $6,000 more than three times the amount in bonds. How mu

kotykmax [81]

Answer:

The amount of investment in bonds is US$ 4,500 and the amount of investment in stocks is US$ 19,500

Step-by-step explanation:

Total investment in stocks and bonds = US$ 24,000

Amount of investment in bonds = x

Amount of investment in stocks = 3x + 6,000 (amount in stocks is $6,000 more than three times the amount in bonds)

For finding the value of x (amount of investment in bonds), we use this equation:

x + 3x + 6,000 = 24,000

x + 3x = 24,000 - 6,000

4x = 18,000

x = 4,500 (dividing by 4)

The amount of investment in bonds is US$ 4,500

Now let's find the amount of investment in stocks:

3x + 6,000 = 3 (4,500) + 6,000 = 13,500 + 6,000 = 19,500

The amount of investment in stocks is US$ 19,500

5 0

2 years ago

Read 2 more answers

Poiseuille's Law states that the volume, V, of blood flowing through an artery in a unit of time at a fixed pressure is directly

eimsori [14]

Answer:

11.58%

Step-by-step explanation:

The initial volume if blood flowing through the artery is given by

$V=kr^4$

To achieve a new volume of 155% (55% increase) of the initial volume, the new radius must be:

$V'= 1.55V\\1.55V=k(r')^4\\1.55kr^4 = k(r')^4\\(\sqrt[4]{1.55}*r)^4=(r')^4 \\(1.1158*r)^4=(r')^4 \\r'=1.1158*r$

Since the new radius is 1.1158 times larger than the initial radius, the percentage increased is:

$I=(1.1158 - 1)*100\%\\I= 11.58\%$

7 0

2 years ago

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

Presumably you should be doing this using calculus methods, namely computing the surface integral along $\mathbf r(u,v)$ .

But since $\mathbf r(u,v)$ describes a sphere, we can simply recall that the surface area of a sphere of radius $a$ is $4\pi a^2$ .

In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
$\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u$

So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
$=-2\pi a^2(\cos\pi-\cos 0)$
$=-2\pi a^2(-1-1)$
$=4\pi a^2$

as expected.

6 0

2 years ago