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kakasveta [241]

2 years ago

13

What is the sale price of a phone that was originally $199 but that has been marked down by 15 percent? $159.15 $159.20 $169.10

$169.15

1 answer:

dsp732 years ago

5 0

Answer:

169.15 is the correct answer

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The mean temperature for the first 4 days in January was 1°C.

soldier1979 [14.2K]

-4 degrees I think.

5 0

2 years ago

Kellianne lined up the interior angles of the triangle along line p below.

Tanzania [10]

Answer:1,4,5,2

Step-by-step explanation:

4 0

2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

b

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

c

The probability, $P =0.0002$

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago

The average time taken to complete an exam, X, follows a normal probability distribution with mean = 60 minutes and standard dev

k0ka [10]

Answer: b. 0.8413

Step-by-step explanation:

Given : The average time taken to complete an exam, X, follows a normal probability distribution with $\mu=60\text{ minutes}$ and $\sigma=30\text{ minutes}$ .

Then, the probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-

$P(x>30)=P(z>\dfrac{30-60}{30})\ \ [\because\ z=\dfrac{x-\mu}{\sigma} ]\\\\=P(z>-1)=P(z-z)=P(Z$

[using z-value table]

Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam = 0.8413

3 0

2 years ago

The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earne

vlada-n [284]

Revenue > Cost
R(x) > C(x)
0.50x > 10+0.20x
0.50x-0.20x > 10
0.30x > 10
x > 10/0.30
x > 33.333 which is approximate

Round up to the nearest whole number to get x = 34. You need to sell at least 34 cups of lemonade to have the revenue R(x) be larger than the cost C(x)

Answer: 34

8 0

2 years ago