The right answer for the question that is being asked and shown above is that: "D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50." Given that a relative frequencies of 0.48 and 0.52, there will be an association between the categorical variables.<span>
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Answer:
C. Probability is 0.90, which is inconsistent with the Empirical Rule.
Step-by-step explanation:
We have been given that on average, the parts from a supplier have a mean of 97.5 inches and a standard deviation of 6.1 inches.
First of all, we will find z-score corresponding to 87.5 and 107.5 respectively as:










Now, we need to find the probability
.
Using property
, we will get:

From normal distribution table, we will get:



Since the probability is 0.90, which is inconsistent with the Empirical Rule, therefore, option C is the correct choice.
∠ M ≅ ∠ R: true
<span>VL ≅ LT: true
</span><span>Δ MLV can be rotated about point L to map it to Δ RLT. : false
</span><span>A series of rigid transformations of Δ MLV maps it to Δ RLT. : true </span>
Answer:
The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549
Step-by-step explanation:
We are in posessions of the sample's standard deviation. So we use the student's t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.0930
The margin of error is:
M = T*s = 2.0930*0.16 = 0.3349.
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 2.92 - 0.3349 = 2.5851
The upper end of the interval is the sample mean added to M. So it is 2.92 + 0.3349 = 3.2549
The 95% confidence interval for the mean GPA of all accounting students at this university is between 2.5851 and 3.2549
She will have to add 3 more dollars so 3 more days