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Alja [10]
2 years ago
8

What is the quotient? StartFraction a minus 3 Over 7 EndFraction divided by StartFraction 3 minus a Over 21 EndFraction StartFra

ction negative (a minus 3) squared Over 147 EndFraction StartFraction (a minus 3) squared Over 147 EndFraction 3 –3
Mathematics
1 answer:
brilliants [131]2 years ago
3 0

Answer:

Correct answer is

\text{Quotient of }\dfrac{a-3}{7}\div\dfrac{3-a}{21} = -3

Step-by-step explanation:

Let us rephrase the given statement mathematically.

We are given the fractions as:

\dfrac{a-3}{7}

to be divided by:

\dfrac{3-a}{21}

<u>To find:</u>

\dfrac{a-3}{7}\div\dfrac{3-a}{21}

Now, let us have a look at the division rule in fractions:

\dfrac{a}{b} \div \dfrac{c}{d}

is equivalent to

\dfrac{a}{b} \times \dfrac{d}{c}

In other words, we say that the second fraction \frac{c}{d} is changed to \frac{d}{c} and \div is changed to \times.

Now solving the given fraction by applying above rules:

\dfrac{a-3}{3}\div\dfrac{3-a}{21}

\Rightarrow \dfrac{a-3}{7}\times \dfrac{21}{3-a}\\\Rightarrow \dfrac{a-3}{7}\times \dfrac{21}{-(a-3)}\\\Rightarrow \dfrac{1}{1}\times \dfrac{3}{-1}\\\Rightarrow -3

So, correct answer is:

\text{Quotient of }\dfrac{a-3}{7}\div\dfrac{3-a}{21} = -3

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2

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Answer:

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