The Given Sequence is an Arithmetic Sequence with First term = -19
⇒ a = -19
Second term is -13
We know that Common difference is Difference of second term and first term.
⇒ Common Difference (d) = -13 + 19 = 6
We know that Sum of n terms is given by : 
Given n = 63 and we found a = -19 and d = 6






The Sum of First 63 terms is 10521
Answer:
the probability that the exceeded 65 = 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
Step-by-step explanation:
<u>Step 1</u>:-
The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.
mean (μ) = 64
standard deviation (σ) =3
by using normal distribution
given (μ) = 64 and (σ) =3
i) when x =65

P( X≥ 65) = P(z≥0.33)
= 0.5 - A(z₁)
= 0.5 - 0.1293 (see normal table)
= 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
We are given the function –2x – 4 + 5x = 8 and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:
-2x + 5x =8+4
Then, do the necessary operations.
3x = 12
x = 4.
The variable x has a value of 4.
Answer:
The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.
Step-by-step explanation:
What is Confidence Interval?
The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.
The confidence interval is given by

Where
is the mean weight
is the standard deviation
is the critical value from t-table and n is the sample size.
The term
is known as margin of error.
As the sample size is decreased the corresponding margin of error increases which results in wider confidence interval which means smaller precision.
The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.
We can say with 95% confidence that the true mean weight of the rock is within the interval of (25.2, 29.1).