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daser333 [38]
2 years ago
4

The product of two numbers is 450. The first number is half the second number. Which equation can be used to find x, the greater

number? = 450 225x2 = 0 x2 = 450 450x2 = 0The product of two numbers is 450. The first number is half the second number. Which equation can be used to find x, the greater number? = 450 225x2 = 0 x2 = 450 450x2 = 0
Mathematics
1 answer:
cestrela7 [59]2 years ago
8 0

Answer:

1/2 x^2 = 450

Step-by-step explanation:

x is the greater number.

The other number is 1/2x.

1/2x * x = 450

1/2 x^2 = 450

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Find the sum of the first 63 terms of –19, -13, -7 …
boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

Given n = 63 and we found a = -19 and d = 6

\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)

\implies S_6_3 = \frac{63}{2}(-38 + (62)6)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(334)

\implies S_6_3 = {63}(167) = 10521

The Sum of First 63 terms is 10521

4 0
2 years ago
The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3. Suppose 36 golfers play
kondaur [170]

Answer:

the probability that the exceeded 65 = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

Step-by-step explanation:

<u>Step 1</u>:-

The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.

mean (μ) = 64

standard deviation (σ) =3

by using normal distribution

given (μ) = 64 and  (σ) =3

i) when x =65

z = \frac{x-mean}{S.D} = \frac{65-64}{3} = 0.33 >0

P( X≥ 65) = P(z≥0.33)

              = 0.5 - A(z₁)

              = 0.5 - 0.1293 (see normal table)

             = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

                                               

6 0
2 years ago
Consider this equation: -2x - 4 + 5x = 8 Generate a plan to solve for the cariable. Describe the steps that will be used.
nordsb [41]
We are given the function –2x – 4 + 5x = 8 and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:

-2x + 5x =8+4
Then, do the necessary operations.

3x = 12
x = 4.
The variable x has a value of 4.
8 0
2 years ago
Find the height of a clock tower if the angle of elevation from a horizontal point 430 m from its base is 40°.
zaharov [31]

\\ \sf\longmapsto tan40=\dfrac{P}{430}

\\ \sf\longmapsto 0.83=\dfrac{P}{430}

\\ \sf\longmapsto P=430(0.83)

\\ \sf\longmapsto P\approx361m

  • P=Height of tower

5 0
2 years ago
Read 2 more answers
Weight of a rock: In a geology course, students are learning to use a balance scale to accurately weigh rocks. One student plans
statuscvo [17]

Answer:

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

Step-by-step explanation:

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.  

The confidence interval is given by

CI = \bar{x} + t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\

Where \bar{x} is the mean weight \sigma is the standard deviation t_{\alpha/2} is the critical value from t-table and n is the sample size.

The term t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) is known as margin of error.

As the sample size is decreased the corresponding margin of error increases which results in wider confidence interval which means smaller precision.

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

We can say with 95% confidence that the true mean weight of the rock is within the interval of (25.2, 29.1).

7 0
2 years ago
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