OK, so this is assuming we are considering that the first three kids to solve ARE NOT in the first day.
So we have 3 kids and it doubles
Day 1 : 6
Day 2 : 12
Day 3 : 24
Day 4 : 48
Day 5 : 96
Day 6 : 192
Day 7: 384
So it should take 7 days or a week to solve all the problems.
The equation:
(3 * 2)^x = 384
Answer:
Step-by-step explanation:
xy = 2y + xy = 0
Hence, 2y + xy = 0 ---------(1)
Differentiating equation (1) n times by Leibnitz theorem, gives:
2y(n) + xy(n) + ny(n - 1) = 0
Let x = 0: 2y(n) + ny(n - 1) = 0
2y(n) = -ny(n - 1)
∴ y(n) = -ny(n - 1)/2 for n ≥ 1
For n = 1: y = 0
For n = 2: y(1) = -y
For n = 3: -3y(2)/2
For n = 4: -2y(3)
Answer:
15.25% probability that Napoleon and Pedro catch the bus and make it to their first period class on time
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this problem, we have that:
Event A: Both Napoleon and Pedro catch the bus, so P(A) = 0.25.
Event B: Making to their first period class on time.
However, the probability that they make it to their first period class on time, given that they catch the bus is 0.61.
This means that 
What is the probability that Napoleon and Pedro catch the bus and make it to their first period class on time
15.25% probability that Napoleon and Pedro catch the bus and make it to their first period class on time
Answer:
Equation shown
Step-by-step explanation:
Eq(1): x-3y=-12
X=-12+3y
=-4+y
Eq(2): x-3y=-6
X=-6+3y
=-2+y
Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}
Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid
For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36
Total amount to be paid in 20 years, A1 = 376.36*20*12 = $90,326.30
For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22
Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98
The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32
Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.
