Which is the best description of the graph of the function f(x) = 60(One-third)x? The graph has an initial value of 20, and each
successive term is determined by subtracting One-third. The graph has an initial value of 20, and each successive term is determined by multiplying by One-third. The graph has an initial value of 60, and each successive term is determined by subtracting One-third. The graph has an initial value of 60, and each successive term is determined by multiplying by One-third.
2 answers:
Answer:
The graph has an initial value of 60, and each successive term is determined by multiplying by One-third.
Step-by-step explanation:
Which is the best description of the graph of the function f(x) = 60(One-third)x?
A. The graph has an initial value of 20, and each successive term is determined by subtracting One-third.
B. The graph has an initial value of 20, and each successive term is determined by multiplying by One-third.
C. The graph has an initial value of 60, and each successive term is determined by subtracting One-third.
D. The graph has an initial value of 60, and each successive term is determined by multiplying by One-third.
Given:
f(x) = 60 (1/3)^x see graph attached.
Examining the graph, we notice that
1. The graph has an initial value of 60, at point (0,60)
2. The graph decreases as x increases. Each successive term is determined by multiplying by 1/3, namely in the sequence
{(0,60), (1,20), (2, 20/3), (3, 20/9), ...}
This means the choice is D (or the fourth one).
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Answer:
Explanation:
The number of different ways in which the<em> two armadillos</em> would be at the ends of the row is 2:
The number of different combinations in which<em> two of the three aardvarks </em>can sit at the ends of the row is P(3,2):
Therefore, there are 2 + 6 = 8 different ways in which the two animlas on the ends of the row were both armadillos or both aardvarks.
Now calculate the total number of different ways in which the animals can sit. It is P(5,5):
Thus, <em>the probability that the two animals on the ends of the row were both armadillos or both aardvarks</em> is equal to the number of favorable outputs divided by the total number of possible outputs: