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Ostrovityanka [42]
2 years ago
9

Write the line of the equation of a line given the slope and intercept(-3,4);m=-1/3

Mathematics
1 answer:
vodomira [7]2 years ago
3 0

Answer: y= -1/3x + 3

Step-by-step explanation:

To write it in slope intercept form we need just the slope and the y intercept. Here we are given the slope but we need to find the y intercept using the coordinates.

Using the slope intercept formula y= mx + b where m is the slope and b is the y intercept.

We will plot in the x and y coordinates and the slope to find the y intercept.

4 = -1/3(-3) + b

4= 1 + b

-1  -1

b =3   The y intercept in this case is 3.

so y = -1/3 + 3

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A potato chip company makes chips to fill snack-size bags and family size bag. in one week production cannot exceed 2400 units,
Ainat [17]

Answer:

600 units of for snack-size, 1800 units for family-size

Step-by-step explanation:

7 0
2 years ago
If the probability is 0.54 that Stock A will increase in value during the next month and the probability is 0.68 that Stock B wi
Aloiza [94]

P(A) =0.54

P(B)= 0.68

P'(A)= 1-0.54 = 0.46

P'(B)= 1- 0.68 = 0.32

The probability of neither of both event will occur:

= P'(A)×P'(B)

=0.46 × 0.32

=0.1472

3 0
2 years ago
Can you Solve this?<br> IF AT=4 CAT=6 CROW=8 BRAIN=10<br><br> TWISTER = ?
Artyom0805 [142]
The answer is 14 there just adding an extra letter each time twister has 7 letters
3 0
1 year ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
What values of c and d make the equation true? RootIndex 3 StartRoot 162 x Superscript c Baseline y Superscript 5 Baseline EndRo
Reil [10]

Answer:

<em>c=6, d=2</em>

Step-by-step explanation:

<em>Equations </em>

We must find the values of c and d that make the below equation be true

\sqrt[3]{162x^cy^5}=3x^2y \sqrt[3]{6y^d}

Let's cube both sides of the equation:

\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3

The left side just simplifies the cubic root with the cube:

162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3

On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

162x^cy^5=3^3x^6y^3 (6y^d)

Simplifying

x^cy^5=x^6y^{3+d}

Equating the powers of x and y separately we find

c=6

5=3+d

d=2

The values are

\boxed{c=6,d=2}

3 0
2 years ago
Read 2 more answers
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