Question

Three identical resistors are connected in series to a battery. If the current of 12 A flows from the battery, how much current flows through any one of the resistors

Answer 1

Answer:

Current that flows through any one of the resistors has a value of 12 amperes.

Explanation:

When a group of resistors are connected in series, the same current flows through each resistor. According to the Ohm's Law, the circuit can be represented as follows:

$V_{batt} = i\cdot (R_{1}+R_{2}+R_{3})$

$i = \frac{V_{batt}}{R_{1}+R_{2}+R_{3}}$

Where:

$V_{batt}$ - Voltage of the battery, measured in volts.

$R_{1}$, $R_{2}$, $R_{3}$ - Electric resistance of the first, second and third resistors, measured in ohms.

$i$ - Current, measured in amperes.

If $R_{1} = R_{2} = R_{3} = R$, then:

$i = \frac{V_{batt}}{3\cdot R}$

Current that flows through any one of the resistors has a value of 12 amperes.