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devlian [24]
2 years ago
5

One liter of paint is needed to cover all 6 sides of a cubical block. How many liters will be needed to cover all 6 sides of a s

econd cubical block whose edge is twice as long as an edge on the first block?
Will mark brainlist
Mathematics
1 answer:
Art [367]2 years ago
6 0

Answer:

4 liters

Step-by-step explanation:

Let's assume that the side lengths of the cubical block are 2 inches.

This means that one of the sides area is 4 in².

Multiplying this by 6 (for there are 6 sides) gets us 24 in².

So one liter of paint covers 24 in².

Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are 2\cdot2 = 4 inches.

So the area of one side is 16 in².

Multiplying this by 6 (as there are 6 sides) gets us 96 in².

To find how many liters of paint this will take, we divide 96 by 24.

96\div24=4

So 4 liters of paint will be needed for the second cubical block.

Hope this helped!

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Fionn observed that 91\%91%91, percent of the background checks he processes are for potential employees who have already interv
kotegsom [21]

Answer:

0.05

Step-by-step explanation:

checked via khan academy

6 0
2 years ago
At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
2 years ago
The radius of a circle is 9.6 in. Find the circumference to the nearest tenth.
tankabanditka [31]

Answer:

19.2

Step-by-step explanation:

9.6*2=19.2

4 0
1 year ago
Given: FGKL is a trapezoid, m∠F=90°, m∠K=120°, FK=LK=a Find: The length of midsegment.
noname [10]

Answer:

  (3/4)a

Step-by-step explanation:

The angle at K is 120°, so the angle at L is its supplement: 60°. That makes triangle FKL an equilateral triangle with a base of FL = a. The vertex at K is centered over the base, so is a/2 from G.

The midsegement length is the average of GK and FL, so is ...

  midsegment = (GK +FL)/2 = (a/2 +a)/2

  midsegment = (3/4)a

8 0
2 years ago
Which graph can be used to find the solution(s) to 8 – 4x = 2x – 4?
Tom [10]

Answer:

The answer in the attached figure

Step-by-step explanation:

Method 1

we have

8-4x=2x-4

Rewrite the equation as a compound system of equations

y=8-4x -----> equation A

y=2x-4 -----> equation B

Using a graphing tool

The solution of the system of equations is the intersection point both graphs

see the attached figure

the solution is x=2

Method 2

we have

8-4x=2x-4

Group terms that contain the same variable and move the constant to the other side of equation

4x+2x=8+4

Combine like terms

6x=12

Divide by 6 both sides

x=2


3 0
2 years ago
Read 2 more answers
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