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baherus [9]
2 years ago
11

Last year Mason Inc. had a total assets turnover of 1.33 and an equity multiplier of 1.75. Its sales were $195,000 and its net i

ncome was $10,549. The CFO believes that the company could have operated more efficiently, lowered its costs, and increased its net income by $5,250 without changing its sales, assets, or capital structure. Had it cut costs and increased its net income in this amount, by how much would the ROE have changed
Business
1 answer:
Lina20 [59]2 years ago
3 0

Answer:

Return on equity (ROE) would have changed by <u>6.27%</u>.

Explanation:

In accounting ratio, we know that:

Asset Turnover = Sales/Total Assets .............................. (1)

From equation (1), we can solve for Total Assets as follows:

Total Assets = Sales / Asset Turnover ............................ (2)

Substituting the values in the question into equation (2), we have:

Total Assets = $195,000 / 1.33 = $146,616.54

Also, we know that:

Equity Multiplier = Total Assets/Total Equity ......................... (3)

We can solve Total Equity from equation (3) as follows:

Total Equity = Total Assets / Equity Multiplier ..................... (4)

Substituting the relevant values into equation (4), we have:

Total Equity = $146,616.54 / 1.75 = $83,780.88

As a result, we have:

Return on Equity = Net Income/Total Equity = $10,549 / $83,780.88 = 0.1259, or 12.59%

If the company had operated more efficiently, we would have:

New net income = Net income + Amount of increase in net income = $10,549 + $5,250 = $15,799

New return on equity = New net Income / Total Equity = $15,799 / $83,780.88 = 0.1886, or 18.86%

Change in return on equity = New return on equity - Return on Equity = 18.86% - 12.59% = 6.27%

Therefore, return on equity (ROE) would have changed by <u>6.27%</u>.

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Answer:

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Explanation:

We have given fixed Cost = $ 38,600

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Contribution margin ratio =\frac{contribution\ margin\ }{sales}

0.3=\frac{$106000 }{sales}

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1 year ago
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The Net Income is $4416.1

Explanation:

The net income is calculated as follows,

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<u>Less:Expenses</u>

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2 years ago
The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
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Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

P(X=0)=(11C0)(0.5)^0 (1-0.5)^{11-0}=0.00049

P(X=1)=(11C0)(0.5)^1 (1-0.5)^{11-1}=0.0054

P(X=2)=(11C0)(0.5)^2 (1-0.5)^{11-2}=0.027

And adding we got:

P(X \leq 2)= 0.033

b) P(X \geq 2)= 1-P(X

And replacing we got:

P(X \geq 2)= =1-[0.00049 +0.0054] = 0.994

c) P(X \leq 1)= 1-P(X

And replacing we got:

P(X \leq 1)=0.00049 +0.0054= 0.0059

Explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest "number of women", on this case we now that:

X \sim Binom(n=11, p=0.5)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we want to find this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

P(X=0)=(11C0)(0.5)^0 (1-0.5)^{11-0}=0.00049

P(X=1)=(11C0)(0.5)^1 (1-0.5)^{11-1}=0.0054

P(X=2)=(11C0)(0.5)^2 (1-0.5)^{11-2}=0.027

And adding we got:

P(X \leq 2)= 0.033

Part b

For this case we want this probability:

P(X \geq 2)

And we can use the complement rule and we got:

P(X \geq 2)= 1-P(X

And replacing we got:

P(X \geq 2)= =1-[0.00049 +0.0054] = 0.994

Part c

For this case we want this probability:

P(X \leq 1)

And we can use the complement rule and we got:

P(X \leq 1)= 1-P(X

And replacing we got:

P(X \leq 1)=0.00049 +0.0054= 0.0059

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Answer

The answer and procedures of the exercise are attached in a microsoft excel document.  

Explanation  

Please consider the data provided by the exercise. If you have any question please write me back. All the exercises are solved in a single sheet with the formulas indications.  

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