draw the graph of linear equation 5y = 3x + 18 on a cartesian plane. From the graph check weather (-2,4) is the solution of the
linear equation or not PLS URGENT ANSWER
1 answer:
Answer:
The point (-2, 4) is not a solution of the linear equation, 5·y = 3·x + 18
Please find attached the required graph of the linear equation 5·y = 3·x + 18 written in the form y = 3/5·x + 18/5
Step-by-step explanation:
The given equation is 5·y = 3·x + 18, from which we have;
y = 3/5·x + 18/5
To draw the graph, we generate for vales of y corresponding to values of x as follows;
x, y
-6, 0
-5, 0.6
-4, 1.2
-3, 1.8
-2, 2.4
-1, 3
0, 3.6
1, 4.2
2, 4.8
3, 5.4
4, 6
5, 6.6
6, 7.2
7, 7.8
8, 8.4
9, 9
10, 9.6
11, 10.2
12, 10.8
13, 11.4
14, 12
15, 12.6
16, 13.2
Therefore, when y = 0, x = -6, when x = 0, y = 3.6, when x = -2, y = 2.4, when y = 4, x = -2, x = 6
Therefore, the point (-2, 4) is not a solution of the linear equation, 5·y = 3·x + 18
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Answer:
The annual difference in the cost between the two cars in gasoline plus monthly payment per month will be $856.67.
Step-by-step explanation:
Car option "A" gets 18 miles per gallon of gas (MPG) and has a monthly payment of $368.
Now, yearly 12000 miles will consume gallons of gas.
Now, if the gas costs $2.89 par gallons, then yearly fuel cost is $(666.67 × 2.89) = $1926.67
Hence, the yearly cost for option A will be $(1926.67 + 368 × 12) = $6342.67.
Now, car option "B" is a hybrid and gets 60 MPG with a monthly payment of $409.
Now, yearly 12000 miles will consume gallons of gas.
Now, if the gas costs $2.89 par gallons, then yearly fuel cost is $(200 × 2.89) = $578
Hence, the yearly cost for option B will be $(578 + 409 × 12) = $5486.
So, the annual difference in the cost between the two cars in gasoline plus a monthly payment per month will be $(6342.67 - 5486) = $856.67. (Answer)
We can solve this problem by using the distance formula. The distance formula is: We can now put in values and solve.