Pi rounded to a whole number would equal three. Circumference equals 2pi*r. The radius in this case is half of the diameter, so 4.5 cm. 2 times pi, or three equals 6 times 4.5 is 27
Answer:
(4+7i)-2i(2+3i) = 10+3i
Step-by-step explanation:
We need to find the expression that is equivalent to the complex number 10+3i.
Option 1. 2i(4-5i)+(1-7i)
=8i-10i²+1-7i
∵ i² = -1
=8i-10(-1)+1-7i
=8i+10+1-7i
=11+i (incorrect)
Option 2. (4+7i)-2i(2+3i)
=4+7i-4i-6i²
=4+7i-4i-6(-1)
=4+7i-4i+6
=10+3i (Correct)
Option 3. (-3+5i)-3i(4+5i)
= (-3+5i)-12i-15i²
= -3+5i-12i-15(-1)
= -3+5i-12i+15
=12-7i (incorrect)
Option 4. 3i(4+7i)+(11+2i)
= 12i+21i²+11+2i
=12i+21(-1)+11+2i
= 12i-21+11+2i
=14i-10 (incorrect)
Hence, the correct option is (B).
That would be 1953.08
diameter = <span>circumference/pi, so reverse it and multiply 622 by 3.14</span>
Answer:
The maximum height is 191.063 ft
Step-by-step explanation:
We can easily solve this question by plotting the graph of the equation below
h(t)=-16t^2+Vt+h
Where
h = initial height = 2ft
V = initial speed = 110 ft/s
t = time in seconds
Please, see attached image below
The maximum height corresponds to
191.063 ft
Answer:
4.979044478499338 × 10²⁶
Step-by-step explanation:
Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.
Combination factorial is define by ⁿCr = 
21 group of mice receiving Drug A can be selected in ⁶⁰C₂₁ = 
(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug
Drug B 21 mice can be chosen with ³⁹C₂₁ = 
( 39 - 21 = 18) remained for control with ¹⁸C₁₈ =
The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ =
×
×
= 4.979044478499338 × 10²⁶