Question

A box of chocolates contains five milk chocolates, three dark chocolates, and four white chocolates. You randomly select and eat three chocolates. The first piece is milk
chocolate, the second is white chocolate, and the third is milk chocolate. Find the probability of this occuring.

Answer 1

Answer:

60/220

Step-by-step explanation:

we use combination,

$(\frac{5}{1} ) \times ( \frac{4}{1} ) \times ( \frac{3}{1} )$

$5 \times 4 \times 3 = 60$

then, all divided by,

$(\frac{12}{3}) = 220$

$60 \div 220$