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patriot [66]
2 years ago
3

Consider the hypothetical chemical reaction represented by the equation 3 A + 2 B → A 3B 2 Which of the following is a correct i

nterpretation of this equation? i. 3 grams of A react with 2 grams of B to form 1 gram of A 3B 2 ii. 3 atoms of A react with 2 atoms of B to form 1 molecule of A 3B 2 iii. 3 moles of A react with 2 moles of B to form 1 mole of A 3B 2
Chemistry
1 answer:
wolverine [178]2 years ago
4 0

Answer:

iii. 3 moles of A react with 2 moles of B to form 1 mole of A 3B 2

Explanation:

A + 2 B → A 3B 2

A chemical equation among other things, gives the stoichiometry of the reaction; that is the relationship between reactants and products.

This relationship is basically stated in moles form the coefficients of the reactants and product.

From the reaction above, we can say;

1 mol of A reacts with 2 mol of B to form 1 mol of A3B2

It cannot be grams because the reactants and products all have different molar masses.

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What are the intermolecular forces between molecules in a liquid sample of sulfur trioxide,SO3?a. hydrogen bonding b. dipole-dip
fgiga [73]

Answer:

dispersion forces

Explanation:

SO3 is a trigonal planar molecule. All the dipoles of the S-O bonds cancel out making the molecule to be a nonpolar molecule.

The primary intermolecular force in nonpolar molecules is the London dispersion forces. As expected, the London dispersion forces is the intermolecular force present in SO3.

Hence SO3 is a symmetrical molecule having only weak dispersion forces acting between its molecules.

8 0
2 years ago
What is the density (in g/L) of a gas with a molar mass of 146.06 g/mol at 1.03 atm and 297k
marshall27 [118]
Lets assume the gas is acting Ideally, then According to Ideal Gas Equation the density is given as,

                                            d  =  P M / R T         -------  (1)
Where;
P  = Pressure =  1.03 atm

M  = Molar Mass =  146.06 g/mol

R  = Gas Constant =  0.08206 atm.L.mol⁻¹.K⁻¹

T  = Temperature =   297 K

Putting Values in eq. 1,

           d  =  (1.03 atm × 146.06 g/mol) ÷ (0.08206 atm.L.mol⁻¹.K⁻¹ × 297 K)

                                          density  =  6.17 g/L
6 0
2 years ago
For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomas
jolli1 [7]

Answer:

4,25% v/v H3PO4

Explanation:

The concentration of phosphoric acid (H3PO4) is expressed as a volume / volume percentage, which means:

%v/v H3PO4 = (mL of pure H3PO4/mL of solution)*100%

In other words, <u>we are only interested in the final volume of the solution to which the phosphoric acid was diluted, regardless of its composition</u>. Which in this case is 1 L (1000 mL).

We can then apply the following equation, commonly used to calculate the initial or final concentration (or volume) of a substance when it is diluted:

Ci*Vi=Cf*Vf

<u>Where</u>:

Ci, is the initial concentration of the substance.

Vi, the initial volume of the substance

Cf, the final concentration reached after dilution

Vf, the final volume of the solution at which the substance was diluted

In this case, the incognite would be the final concentration of H3PO4 reached after dilution, that is, Cf. Therefore, we proceed to clear Cf from the previous equation and replace our data:

Cf = (Ci*Vi)/Vf = (85% v/v * 50 mL)/1000 mL = 4,25 % v/v

Note that being up and down in the division, the mL unit is canceled to result in% v / v.

7 0
2 years ago
Write an equation for the formation of bf3(g) from its elements in their standard states.
blagie [28]
In nature, boron is monoatomic. Therefore, its formula is B.
On the other hand, fluorine is diatomic. Therefore, its formula is F2

Now, the basic unbalanced equation is:
B + F2 .........> BF3

Now, we need to balance this equation. As you can see, we have two fluorine moles entering the reaction and 3 formed in the products.
Balancing the equation, we will reach the following balanced reaction:
2B + 3F2 .......> 2BF3 
7 0
2 years ago
7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?
suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

                 n  =  0.8133 mol

4 0
2 years ago
Read 2 more answers
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