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Westkost [7]
2 years ago
3

Tech A says that batteries should be charged as fast as possible. Tech B says that the ideal charging rate is the CCA divided by

70. Who is correct?
Physics
1 answer:
8090 [49]2 years ago
3 0

Answer:

Neither A nor B

Explanation:

The charge rate of a battery is the rate at which charge is added to the battery in a given time unit. The unit of charge rate is Coulombs/second or amps

The time to charge a battery, is given by  the battery charging formula which is given as follows;

Battery charging time, t = Battery Ah(Ampere hour)/(Charging current, A)

T = Ah/A

Where;

T = Time (Hours)

Ah = The rating of the battery in Ampere Hour

A = The Current applied given in Amperes

The charging current should 10% of the Ah battery rating, such that a 120 Ah battery requires about 12 Amperes charging current

However, due to losses in the system, the current can be set at 13A

the time for charging will then be t = 120/13 = 9.23 hours

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Two sources emit beams of light of wavelength 550 nm. The light from source A has an intensity of 10 μW/m2, and the light from s
alexira [117]

Answer:

<em>A) Beam B carries twice as many photons per second as beam A.</em>

Explanation:

If we have two waves with the same wavelength, then their intensity is proportional to their power, or the energy per unit time.

We also know that the amount of photon present in an electromagnetic beam is proportional to the energy of the beam, hence the amount of beam per second is proportional to the power.

With these two facts, we can say that the intensity is a measure of the amount of photon per second in an electromagnetic beam. So we can say that <em>beam B carries twice as more power than beam A, or Beam B carries twice as many photons per second as beam A.</em>

3 0
2 years ago
An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, s
max2010maxim [7]

Answer:

xmax = 9.5cm

Explanation:

In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.

In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

F_e=qE=ma             (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

x_{max}=v_o\sqrt{\frac{2d}{a}}             (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm

The horizontal distance traveled by the electron is 9.5cm

4 0
2 years ago
A truck pulled a car of 2,350 kg a distance of 25 meters. If the car accelerates from 3 m/s to 6 m/s, whats the average force ex
faust18 [17]

Answer:

1,269 N

Explanation:

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2 years ago
Volcanoes are often formed at plate boundaries. This is a convergent plate boundary. From the choices listed, pick the correct d
katen-ka-za [31]
Your answer should be a
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2 years ago
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Two circular rods, one steel and the other copper, are joined end to end. Each rod is 0.750 m long and 1.50 cm in diameter. The
Eddi Din [679]

Answer:

(a) Steel rod: 1.1 * 10^{-4}

    Copper rod: 1.88 * 10^{-4}

(b) Steel rod: 8.3 * 10^{-5} m

Copper rod: 1.41 * 10^{-4} m

Explanation:

Length of each rod = 0.75 m

Diameter of each rod = 1.50 cm = 0.015 m

Tensile force exerted = 4000 N

(a) Strain is given as the ratio of change in length to the original length of a body. Mathematically, it is given as

Strain = \frac{1}{Y} * \frac{F}{A}

where Y = Young modulus

F = Fore applied

A = Cross sectional area

For the steel rod:

Y =  200 000 000 000 N/m^{2}

F = 4000N

A = \pi r^{2}      (r = d/2 = 0.015/2 = 0.0075 m)

=> A = \pi * (0.0075)^{2}

=> A = 0.000177 m^{2}

∴ Strain = \frac{4000}{200000000000 * 0.000177} \\\\Strain = \frac{4000}{35400000}\\ \\Strain = 0.000113 = 1.13 * 10^{-4}

For the copper rod:

Y =  120 000 000 000 N/m²

F = 4000N

A = \pi r^{2}      (r = d/2 = 0.015/2 = 0.0075 m)

=> A = \pi * (0.0075)^{2}

=> A = 0.000177 m^{2}

Strain = \frac{4000}{120 000 000 000 * 0.000177} \\\\Strain = \frac{4000}{21240000}\\ \\Strain =  = 1.88 * 10^{-4}

(b) We can find the elongation by multiplying the Strain by the original length of the rods:

Elongation = Strain * Length

For the steel rod:

Elongation = 1.1 * 10^{-4} * 0.75 = 8.3 * 10^{-5} m

For the copper rod:

Elongation = 1.88 * 10^{-4} * 0.75 = 1.41 * 10^{-4} m

6 0
2 years ago
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