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baherus [9]
2 years ago
7

Which of the following is required by k-means clustering ? a. defined distance metric b. number of clusters c. initial guess of

centroids d. all of the above
Mathematics
1 answer:
mestny [16]2 years ago
6 0

Answer:

d. all of the above

Step-by-step explanation:

K-means clustering is a term used to describe a technique of vector quantization, that attempts to partition "n" observations into "k" clusters whereby each observation refers to the cluster with the closest mean which represents a model of the cluster.

This implies that the K-means algorithm recognizes the "k" number of centroids, and then assigns every data point to the closest cluster while the centroids remain as small as possible.

Hence, the following is required of K-means clustering:

1. defined distance metric

2. number of clusters

3. initial guess of centroids

Therefore, in this case, the correct answer is option D: All of the above.

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John Simone is buying a used car for a total cost of $11,805.00. He’s making a down payment of $1,500.00 and borrowing the remai
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1,500+343(3×12)=13,848
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1500+12,348= 13,848
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Rachael ordered early learning software for her daughter from an online retailer. Each item costs $6.50, and there is a shipping
natta225 [31]

Answer:

Step-by-step explanation:

(a)

Total cost = (7 items * Cost per item) + Shipping fee = 7*6.5 + 8.5 = $54

(b)

Modelling the above equation with symbols:

c = s*6.5 + 8.5 = 6.5s + 8.5

(c)

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A sociologist is studying the social media habits of high school students in a school district. The sociologist wants to estimat
Sindrei [870]

Answer:

A one-sample t-interval for a population mean

Step-by-step explanation:

As the question is "How many minutes per day, on average, do you spend visiting social media sites?", the answer will be in a numerical form (number of hours, positive integer or real number).

As this is not a proportion, the option "A one-sample t-interval for a population mean" is discarded.

As the study does not defined another variable to compare in pairs, it is not a matched-pairs test. Option "A matched-pairs t -interval for a mean difference" discarded.

There are not two means in the study, so there is no "difference between means" variable. Options "A two-sample z-interval for a difference between proportions" and "A two-sample t-interval for a difference between means".

This should be a  one-sample t-interval for a population mean, as there is only one sample, one population mean and the population standard deviation is not known.

3 0
2 years ago
The lines –2y = – 3/5 and y = 4x + 5/3 are
MrRa [10]

Answer:

c.) neither

Step-by-step explanation:

-2y = -3/5 does not have an x value for a slope to contrast with y = 4x + 5/3

5 0
2 years ago
Find the equation of the plane through the point (2,5,7) that is parallel to the line r=(3i+2j−2k)+t(i+2j+9k) and perpendicular
insens350 [35]

The plane we want to find has general equation

a(x-2)+b(y-5)+c(z-7)=0

with a,b,c not equal to 0, and has normal vector

\vec n=a\,\vec\imath+b\,\vec\jmath+c\,\vec k

\vec n is perpendicular to both the normal vector of the other plane, which is 4\,\vec\imath+5\,\vec\jmath+6\,\vec k, as well as the tangent vector to the line \vec r(t), which is \vec\imath+2\,\vec\jmath+9\,\vec k.

This means the dot product of \vec n with either vector is 0, giving us

\begin{cases}4a+5b+6c=0\\a+2b+9c=0\end{cases}

Suppose we fix c=1. Then the system reduces to

\begin{cases}4a+5b=-6\\a+2b=-9\end{cases}

and we get

(4a+5b)-4(a+2b)=-6-4(-9)\implies-3b=30\implies b=-10

a+2(-10)=-9\implies a=11

Then one equation for the plane could be

\boxed{11(x-2)-10(y-5)+(z-7)=0}

or in standard form,

\boxed{11x-10y+z=-21}

The solution is unique up to non-zero scalar multiplication, which is to say that any equation (11x-10y+z)k=-21k would be a valid answer. For example, suppose we instead let c=2; then we would have found a=22 and b=-20, but clearly dividing both sides of the equation

22(x-2)-20(y-5)+2(z-7)=0

by 2 gives the same equation as before.

7 0
2 years ago
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