Answer:
The claim is not fair because:
- Probability of roliing two 6s = Probability of rolling two 3s = 1/36
Step-by-step explanation:
The <em>probaility</em> of an event is defined as the number of favorable outcomes divided by the number of total possible events.
P (event E) = number of outcomes for event E / number of possible events
1. <u>As </u><u>first step</u><u>, you may draw a table to find the </u><u>sample space</u><u> (set of all possible outcomes)</u>.
<u>Sample space</u>
The results of the rolling two dice are summarized in this table:
Second roll 1 2 3 4 5 6
First roll
1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
3 (3,1) (3,2) <u>(3,3)</u> (3,4) (3,5) (3,6)
4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
6 (6,1) (6,2) (6,3) (6,4) (6,5) <u>(6,6)</u>
<u></u>
2.<u>Now, in that table, you can observe</u>:
The results (3,3) and (6,6) are highlited.
a) Total number of events: 6 × 6 = 36
b) Nnmber of outcomes for the event rolling two 6s (6,6): 1
c) Number of outcomes for the event rolling two 3s (3,3): 1
3) <u>Next, you can calculate the probabilities:</u>
a) Probability rolling two 6s = 1 / 36
b) Probability of rolling two 3s: 1 / 36
4. <u>Conclusion</u>: the probabilities prove that rolling two 6s is just as likely as rolling two 3s.
