Answer: she must complete 4 levels to have a point fewer than 20
Step-by-step explanation:
Given the following :
Starting point = 100 points
Passing a level = - 8 points
Catching a flower = - 3 points
Suppose Tina catches 6 flowers per level
Number of levels she must complete to have fewer Than 20 points
Total number of points lost per level:
Catching 6 flowers = -(6 × 3)
Passing the level = - 8
= - 18 + - 8 = - 26 points
Number of levels she must complete to have < 20
Let number of levels = y
Starting points - (26 × number of levels) < 20
100 - (26y) < 20
100 - 26y < 20
-26y < 20 - 100
-26y < - 80
y > 80/26
y > 3.07
Hence she must complete 4 levels to have a point fewer than 20
Answer:
In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.
Step-by-step explanation:
Given:
Cost of movie pass = $40
Cost per matinees with pass = $1.00
Cost per matinees without pass = $3.50
To Find:
Number of times must Seth attend in order for it to benefit his father to buy the pass = ?
Solution:
Let x be the number of times he wants to visit
To profit his father
The number of visits without pass = the number of visits with passin the cost of $3.50
Then, without pass if he visits for x times then the cost will be = 3.50x
Also with pass, the number of times he can visit the pass = 
then



x = 11.42
x = 11 (approx)
For this question my answer would be
g(x)=(1.6)x-9+5
Hope this Helps
Answer:
a. 205320
b. 34220
c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
Step-by-step explanation:
a) The number of ways to dustribute exams among the TA's is:
n / (n - r)!
n= number of things to choose from
r= Choosing r number
60P3= 60! / (60 - 3)!
(60)(59)(58)(57)! / (57)!
=205320
B) The number of ways to dustribute the exams among the TA's is:
n! /(n - r)! r!
60C3= 60! /(60 - 3)! 3!
= 60!/ 57! 3!
= 60 × 59 × 58 / 3 × 2 × 1
= 34220
C) The required number of ways is:
60C25 + 60C20 + 60C15
= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
The statement "<span>The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4
To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
![y= \sqrt[5]{Bx+C}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%5B5%5D%7BBx%2BC%7D%20)
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