The right answer is:
<em>area B = area C</em>
We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.
Answer:
11
Fifth term
Step-by-step explanation:
The third term is:
20 − (3)² = 11
If the term is negative:
20 − n² < 0
n² > 20
n > √20
n > 4.47
The first term to have a negative value is the fifth term.
V=hpir^2
r=10
v=6283
6283=hpi10^2
6283=100hpi
divide both sides by 100
62.83=hpi
aprox pi=3.141592
divide both sides by pi
19.9994143=h
so about 20 inches
When you divide, the exponents subtract. -9 - (-12) = 3
3^3 = 27.
