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ozzi
2 years ago
6

The expression x4 + 6x3 – 11x2 – 60x + 100 is equivalent to (x – 2)(x – 2)(x + 5)(x + 5). At what points does the graph of the f

unction f(x) = x4 + 6x3 – 11x2 – 60x + 100 intersect the x-axis?
Mathematics
2 answers:
telo118 [61]2 years ago
8 0

Answer:

(2,0) and (-5,0)

Step-by-step explanation:

Since, if (x-a) is the factor of a polynomial then the graph of the polynomial intersects the x-axis at (a,0).

Here, the given polynomial,

x^4+6x^3-11x^2-60x+100

According to the question,

x^4+6x^3-11x^2-60x+100=(x-2)(x-2)(x+5)(x+5)

⇒ (x-2) and (x+5) are the factors of the given polynomial,

By the above statement,

The points at which the graph of the given function intersects the x-axis are,

(2,0) and (-5,0)

nikdorinn [45]2 years ago
6 0
Since y equals the product of the factors, any value for x which makes any factor equal to zero is a point where the graph touches the x-axis.

x=-5 and 2  (technically the points (-5,0) and (2,0))
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Answer:

Option B is the correct answer.

Step-by-step explanation:

Jen decides to read 100 pages the first day and 50 pages each day thereafter.

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Option A:

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Option B:

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Option C:

Ariel read 20 pages less the first day than Jen read.

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Option D:

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6 0
2 years ago
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Adam is working two summer jobs, making $9 per hour washing cars and $8 per hour walking dogs. Last week Adam earned a total of
Phantasy [73]

Answer:

Washing cars= 4 hours

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Step-by-step explanation:

You want to start by creating equations. So one thing we know is that he makes $9 an hour washing cars(x) and $8 walking dogs(y).

$9x+$8y=$116

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y=x+6

Now You plug what y equals into the first equation to solve for x.

9x+8(x+6)=116     Next distribute the 8 to each term.

9x+8(x)+8(6)=116

9x+8x+48=116     Add the like terms together (9x+8x)

17x+48=116         Subtract the 48 from both sides

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17x=68             Now divide by 17 on both sides.

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17    17

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y=(4)+6

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2 years ago
Alexandra's bank statement shows a closing balance of $130.68. There are no outstanding checks or deposits. Her checkbook shows
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2 years ago
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Find a right triangle that has legs with your irrational Lengths and a hypotenuse with a rational Length
cluponka [151]

gg easy


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let's find some stuff

one easy way is to find a rational value for c find values of a and b

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now split up 25 into 2 things that don't have rational square roots

if we say a^2=19 and b^2=6 then we get

a=\sqrt{19} and b=\sqrt{6} (which are both irrational)

4 0
2 years ago
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