Question

Find the number if 18 is taken away from 8 times of a number gives 30.

Answer 1

Answer:

Let the number be x.

8 times that number would be 8x, and taking away 18 from it 8x - 18. Knowing the result of doing this is 30, we can write the following equation:

8x - 18 = 30

And solve it. First we pass the -18 to the sight umming:

8x = 30 + 18

8x = 48

Then the 8 which is multiplying to the right dividig:

x = 48/8 = 6

Now we verify we have done it preporly:

8x - 18 = 30

8 * 6 - 18 = 30

48 - 18 = 30 TRUE

Answer 2

Answer:

x =6

Step-by-step explanation:

Translate into algebraic equation =

$8(x)-18= 30\\= 8x-13=30$

Let's solve for x

$\mathrm{Add\:}18\mathrm{\:to\:both\:sides}\\8x-18+18=30+18$

Simplify

$8x=48$

Divide both sides by 8

$\frac{8x}{8}=\frac{48}{8}$

Simplify

$x =6$