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Grace [21]
2 years ago
10

A measuring cylinder of radius 3.5cm contains water to a height of 56cm. If this water is poured into a similar cylinder of radi

us 14cm, what will be the height of the water column​

Mathematics
1 answer:
Likurg_2 [28]2 years ago
3 0

Answer:

3.5cm

Step-by-step explanation:

Please see attached picture for full solution.

Volume of cylinder= πr²h, where r is the radius and h is the height.

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Use the formula t=ln2/k that gives the time for a population, with a growth rate k, to double, to answer the following question.
Arturiano [62]

Answer:

  • k = 0.005
  • doubling time ≈ 139 years

Step-by-step explanation:

Matching the form

  A = A0·e^(kt)

to the given equation

  A = 8·e^(.005t)

we can identify the value of k as being 0.005.

  k = 0.005

___

The doubling time is given by the formula ...

  t = ln(2)/k = ln(2)/0.005 ≈ 138.63

It will take about 139 years for the population to double.

3 0
2 years ago
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.
slavikrds [6]
Cos ( ∠C ) = 5/13 = 0.38462
m ∠C = cos^(-1) 0.38642 = 67.4°
m ∠A = 90° - 67.4° = 22.6°
m ∠C - m ∠A = 67.4° - 22.6° = 44.8°
Answer:
B ) 44.8° 
7 0
2 years ago
Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat
Ksenya-84 [330]

Answer:

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

5 0
1 year ago
Solve X-9+2wx=y for x
maxonik [38]
X - 9 + 2wx = y Add 9 to both sides x + 2wx = y + 9 Factor out the x x (1 + 2w) = y + 9 Divide both sides by (1 + 2w) x = (y + 9) / (1 + 2w)
8 0
2 years ago
Read 2 more answers
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Alona [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

4 0
2 years ago
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