Answer:
estimated error=±0.725
Step-by-step explanation:
Side of the triangle= 12cm
Opposite of triangle x= 30
h= hypotenose side
Error= =±1
From trigonometry
Sin(x)=opposite/hypotenose
hypotenose=opposite/sin(x)
h=12/sin(x)
h=12Csc(x)
dh=-12Csc(x)Cot(x) dx...............eqn(1)
dx is the possible error in angle measurements
So we need to convert to radius
dx=±1°× (π/180)
=±1°(π/180)
Substitute x and dx into equation (1)
dh= - 12Csc30°Cot30°×[±(π/180)]
= -12(2)(√3)(±(π/180)
==±0.725
Therefore, estimated error=±0.725
Answer:
15.43 ft
Step-by-step explanation:
To solve this question, one should use the concept of similar triangles.
The pole's shadow and the distance to the ground (x) form a similar triangle to the distance of the plumb bob from the base and the length of the plumb bob, respectively. Note that we do not need to know the measurements of the third side of the triangles to solve the problem. Therefore, the distance of the top of the pole to the ground is:


The distance of the top of the pole to the ground is 15.43 ft.
Answer:
Step-by-step explanation:
some rules of logarithmic function


vice-versa 
If ㏑(a) = ㏑(b), then a = b
∴ 
Use the 2nd rule to simplify it

2㏑(2x) - ㏑(10x) = ㏑(30)
Use the 3rd rule in the 1st term
∵ 2㏑(2x) = ㏑(2x)² = ㏑(4x²)
∴ ㏑(4x²) - ㏑(10x) = ㏑(30)
- Use the 1st rule with the left hand side

Use the 4th rule

Multiply both sides by 5
∴ 2 x = 150
- Divide both sides by 2
∴ x = 75
The value of x = 75
Answer:
Amplitude increases and the period decreases
Step-by-step explanation:
Here, we are to compare amplitude change and period change
The first equation is;
y = sin x
The second is
y = 3 sine (2/3)x
Generally, the equation of a sine graph can be written as;
y = a sin (bx + c)
where a represents the amplitude and b refers to the period
In the first equation , a = 1 while in the second , a = 3 ; This shows an amplitude increase
In the first equation, b = 1 while in the second equation b = 2/3; this shows a period decrease