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2 years ago

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The boiling point of another member of this homologous series was found to be 309 KK. What is the likely molecular formula for t

his compound?

1 answer:

Ganezh [65]2 years ago

8 0

Answer: Pentane C5H12

Explanation:

The boiling point of a substance is simply defined as the temperature whereby a liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid will changes into vapor.

The likely molecular formula for this compound is Pentane i.e C5H12 due to the fact that its boiling point is between Butane with formula C4H10 and Hexane with formula C6H14 boiling points.

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Which parts of acetylsalicylic acid are rigid??

kolezko [41]

The correct answer of the given question above about acetylsalicylic acid would be t<span>he C double bonds with O and the ring structure are </span>rigid<span>. The parts of acetylsalicylic acid that are rigid are the C double bonds with O and the ring structure. Hope this answer helps. </span>

5 0

1 year ago

Read 2 more answers

2 attempts left select the single best answer. The radii of the lithium and magnesium ions are 76 pm and 72 pm, respectively. Wh

Lina20 [59]

The ionic character of any compound depend on the lattice energy as well as the electronegativity of element present in that compound.

More would be the lattice energy more would be ionic nature of that compound.

The lattice energy of any compound is inversely proportional to the ionic radii cation and anion.

In given case the ionic radii of oxide in both oxides would be equal therefore the lattice energy only depend on the ionic radii of cation.

$Lattice energy (U) = \frac{1}{Ionic radii}$

As the radii of Magnesium less then radii of lithium therefore lattice energy of Magnesium oxide would be more than lithium oxide.

Hence, MgO would be more ionic in nature than $Li_{2}O$

8 0

1 year ago

Industrial production of nitric acid, which is used in many products including fertilizers and explosives, approaches 10 billion

mylen [45]

Answer: $9.361\times 10^{4} kJ$

Explanation:

The balanced chemical equation :

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$ $\Delta H^0_{rxn}=-902.0kJ$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{7.056\times 10^3g}{17g/mol}=415.1moles$

According to stoichiometry:

4 moles of $NH_3$ produces = 902.0 kJ of energy

415.1 moles of $NH_3$ produces = $\frac{902.0}{4}\times 415.1=9.361\times 10^{4} kJ$ of energy

Thus the change in enthalpy is $9.361\times 10^{4} kJ$

5 0

2 years ago

What is the hybridization of the central atom in each of the following? 1. Beryllium chloride 2. Nitrogen dioxide 3. Carbon tetr

Lina20 [59]

Answer :

(1) The hybridization of central atom beryllium in $BeCl_2$ is, $sp$

(2) The hybridization of central atom nitrogen in $NO_2$ is, $sp^2$

(3) The hybridization of central atom carbon in $CCl_4$ is, $sp^3$

(4) The hybridization of central atom xenon in $XeF_4$ is, $sp^3d^2$

Explanation :

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the following molecules.

(1) The given molecule is, $BeCl_2$

$\text{Number of electrons}=\frac{1}{2}\times [2+2]=2$

The number of electron pair are 2 that means the hybridization will be $sp$ and the electronic geometry of the molecule will be linear.

(2) The given molecule is, $NO_2$

$\text{Number of electrons}=\frac{1}{2}\times [4]=2$

If the sum of the number of sigma bonds, lone pair of electrons and odd electrons present is equal to three then the hybridization will be, $sp^2$ .

In nitrogen dioxide, there are two sigma bonds and one lone electron pair. So, the hybridization will be, $sp^2$ .

(3) The given molecule is, $CCl_4$

$\text{Number of electrons}=\frac{1}{2}\times [4+4]=4$

The number of electron pair are 4 that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral.

(4) The given molecule is, $XeF_4$

$\text{Number of electrons}=\frac{1}{2}\times [8+4]=6$

Bond pair electrons = 4

Lone pair electrons = 6 - 4 = 2

The number of electrons are 6 that means the hybridization will be $sp^3d^2$ and the electronic geometry of the molecule will be octahedral.

But as there are four atoms around the central xenon atom, the fifth and sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square planar.

3 0

1 year ago

When working with food, personal items such as a cell phone should be

ratelena [41]

Answer:

should be put away in a bag or a pocket away from the food

Explanation:

5 0

1 year ago