Through the complete electrolysis of a sample of pure water, a student collects 14.0 grams of hydrogen gas and 112.0 grams of ox
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Mass of potassium hydrogen pthalate KHP is 0.4856 g, its molar mass is 204.22 g/mol, number of moles of KHP can be calculated as follows:
Here, m is mass and M is molar mass, putting the values,
This will be number of moles of NaOH at equivalent point.
Detailed calculations:
Molarity is defined as number of moles in 1 L of solution, for 250 mL of solution, molarity will be:
For 25 mL, apply dilution law as follows:
Putting the values,
On rearranging,
Convert molarity into number of moles,
At equivalent point, number of moles of KHP will be equal to NaOH, thus, number of moles of NaOH will be 0.00237 mol.
Calculation for molarity:
Volume of NaOH is 18.75 mL, thus, molarity can be calculated as follows:
Putting the values,
Therefore, molarity of NaOH is 0.1264 M
Answer:
E = h v = 6.626 x x 97.20 x
= 6.44 x
J = 4.01 x
eV
n = Energy Level = / E = -13.6 / 4.01 x
= 3.39 x
= 1.84 x
energy level...
Answer:
The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass
Explanation:
2.23 M aqueous solution of NaCl means there are 2.23 moles of NaCl in 1000 mL of solution.
We know that density is equal to ratio of mass to volume.
Here density of solution is 1.01 g/mL.
So mass of 1000 mL solution = () g = 1010 g
molar mass of NaCl = 58.44 g/mol
So mass of 2.23 moles of NaCl = () g = 130.3 g
% by mass is ratio of mass of solute to mass of solution and then multiplied by 100.
Here solute is NaCl.
So % by mass of 2.23 M aqueous solution of NaCl = % = 12.90%