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2 years ago

Imagine that a new polyatomic anion called "platoate" is invented. What would an acid of "platoate" be named?

Chemistry

2 answers:

o-na [289]2 years ago

8 0

<h3>Answer:</h3>

Platoic Acid

<h3>Explanation:</h3>

While naming Carboxylic Acids we know that when the Carboxylic Acid looses proton it is converted into corresponding conjugate base called as Carboxylate.

Examples:

HCOOH → HCOO⁻ + H⁺

Formic acid Formate Ion

H₃CCOOH → H₃CCOO⁻ + H⁺

Acetic acid Acetate Ion

H₅C₂COOH → H₅C₂COO⁻ + H⁺

Propanoic acid Propanoate Ion

Therefore, if the conjugate base is Platoate then the corresponding acid will be Platoic Acid means we will replace the -ate by -ic acid i.e.

RCOO⁻ + H⁺ → RCOOH

Platoate Ion Platoic Acid

nordsb [41]2 years ago

8 0

It would be platonoic acid

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An increase in temperature will effect vapor pressure by:

-BARSIC- [3]

Answer: Increases.

Explanation: As the temperature of a liquid or solid increases its vapor pressure also increases. Conversely, vapor pressure decreases as the temperature decreases.

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2 years ago

If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4

statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

Step 1: Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

Step 2: Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

Step 3: Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

Step 4: Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

Step 5: Calculate Q

Q = [Ca2+] [SO42-]

[Ca2+]= 0.050 M [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

This means precipitation will occur

Step 6: Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

Step 7: Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

Step 8: Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

Step 9: Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

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2 years ago

Barry Bonds swings a bat which has a mass of 1.5 kg at a velocity of 55 m/s. How many joules of kinetic energy could he give to

larisa86 [58]

KE = mv2
2
KE = ? J
m = 1.5 kg
v = 55 m/s
KE = 1.5 kg x (55 m/s)2
2
KE = 2,268.75 J

8 0

2 years ago

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Vilka [71]

Answer:

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Taking The molecular weight of NaCl = 58.44 grams/mole

Determine how many grams of NaCl to prepare the bath solution

first we will calculate the moles of NaCl that is contained in 6L of 170 mM of NaCI solution

= ( 6 * 170 ) / 1000

= 1020 / 1000 = 1.020 moles

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= moles of NaCl * molar mass of NaCl

= 1.020 * 58.44

= 58.61 grams

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=PCl_5%20%5Crightleftarrows%20PCl_3%20%2B%20Cl_2" id="TexFormula1" title="PCl_5 \rightleftarrow

Butoxors [25]

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Explanation:

We are given:

Initial moles of phosphorus pentachloride = 1.00 atm

For the given chemical reaction:

$PCl_5\rightleftharpoons PCl_3+Cl_2$

By Stoichiometry of the reaction:

1 mole of $PCl_5$ produces 1 mole of $PCl_3$ and 1 mole of chlorine gas

So, 1.00 atm of $PCl_5$ will also produce 1.00 atm of $PCl_3$ and 1.00 atm of chlorine gas when the reaction goes to completion.

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Hence, the total pressure of the container will be 2.00 atm

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2 years ago