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Crazy boy [7]
2 years ago
13

What is the mass of nickel(ii) nitrate (182.71 g/mol) dissolved in 25.0 ml of 0.100 m ni(no3)2 solution?

Chemistry
2 answers:
Rashid [163]2 years ago
8 0

Answer : The mass of nickel(II) nitrate is, 0.4568 grams

Explanation : Given,

Molar mass of nickel(II) nitrate = 182.71 g/mole

Volume of solution = 25.0 ml

Molarity = 0.100 M

Molarity : It is defined as the mass of solute present in one liter of solution.

Formula used :

Molarity=\frac{w\times 1000}{M\times V}

where,

w = mass of nickel(II) nitrate

M = molar mass of nickel(II) nitrate

V = volume of solution

Now put all the given values in the above formula, we get:

0.100=\frac{w\times 1000}{182.71\times 25.0}

w=0.4568g

Therefore, the mass of nickel(II) nitrate is, 0.4568 grams

Studentka2010 [4]2 years ago
4 0
The mass  of  ni(NO3)2  that  dissolved  in  25.0 ml  of 0.100m  ni(NO3)2  solution  is  calculated  as   follows

fin  the  number  of  moles   =  molarity   x  volume in  liters

=25  x0.100/ 1000= 2.5  x10^-3  moles
mass  =  mass  x  molar  mass
= 2.5  x10^-3 moles x  182.71 g/mol  = 0.457  grams
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It take 3.5 *10² min

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4.7A

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 ⇒ t = time in seconds.

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