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Pachacha [2.7K]
2 years ago
10

From the options provided for each element below, choose the properties that it may have based on its location in the periodic t

able. Fluorine (F):
A.) highly reactive nonmetal
B.)shiny
C.) aconductor

ANSWER IS: option A
Chemistry
2 answers:
drek231 [11]2 years ago
5 0

Answer: highly reactive nonmetals

Explanation:

Mashutka [201]2 years ago
4 0

<u>Answer: </u>The correct answer is Option A.

<u>Explanation:</u>

Fluorine is the 9th element in the periodic table which belongs to group 17 and period 2. It is a non-metal because it requires an electron to gain its stable electronic configuration.

The electronic configuration of this elements is: 1s^22s^22p^5

This element requires 1 electron to attain stable configuration. It is an insulator  and is not lustrous.

This element easily gains an electron and hence, is considered as a highly reactive non-metal.

Hence, the correct answer is Option A.

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Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as
klio [65]

  The empirical   formula  of hydrocarbon is C₃H₈

The  molecular formula of hydrocarbon   is C₆H₁₆


<u><em> Empirical  formula  calculation</em></u>

Hydrocarbon  contain  carbon and hydrogen

  Step 1:  find the  mass  carbon (C) in carbon dioxide (CO₂)  and hydrogen (H )  in water

mass of  of element = molar mass  of element/ molar mass molecule x total mass of    molecule

From periodic table the molar mass  of C =12,    for CO₂ = 12+( 16 x2) =44 g/mol,     for H = 1.00 g/mol,    for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom  of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H  is therefore =  2/18 x 1.442 =0.1602 g


Step 2:  find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060  moles

moles of H  =  0.1602÷ 1 g/mol = 0.1602 moles


Step 3: find the mole ratio  of C and H by dividing  each  mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

  For H = 0.1602/0.06 =2.67

multiply   by 3  to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈


<u><em>The molecular formula calculation</em></u>

[C₃H₈]n  = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂   = C₆H₁₆



7 0
2 years ago
Read 2 more answers
Determine the mass of oxygen in a 7.20 g sample of Al2(SO4)3.
Mekhanik [1.2K]

Given:

7.20 g sample of Al2(SO4)3

Required:

Mass of oxygen

Solution:

                Since you are not given a chemical reaction, just base your solution to the chemical formula given.

Molar mass of Al2(SO4)3 = 342.15 g/mol

7.20 g Al2(SO4)3 (1 mol/342.15g)(3mol O/2 mol Al)(1 mol O2/1/2 mol O2)(32g O2/1mol O2) = 4.04 g O2

5 0
2 years ago
Read 2 more answers
The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution i
bija089 [108]

Answer:

110ml

Explanation:

<em>Using the dilution equation, C1V1 = C2V2</em>

<em>Where C1 is the initial concentration of solution</em>

<em>C2 is final concentration of solution</em>

<em>V1 is intital volume of solution</em>

<em>V2 is final volume of solution.</em>

From the question , C1=6M, C2=0.5M, V1=10ml, V2=?

V2 =\frac{C1V1}{C2}

V2 =\frac{10*6}{0.5}

V2 =120ml

volume of water added = final volume -initial volume

                                    = 120-10

                                   =110ml

3 0
2 years ago
a student adds 3.5 moles of solute to enough water to make a 1500mL solution. what is the concentration?
aksik [14]
<h2>Hello!</h2>

The answer is:

MolarConcentration=\frac{3.5moles}{volume(1.5L)}=2.33molar

<h2>Why?</h2>

Since there is not information about the solute but only its mass, we need to assume that we are calculating the molar concentration of a solution or molarity. So, need to use the following formula:

MolarConcentration=\frac{mass(solute)}{volume(solution)}

Now, we know that the mass of the solute is equal  3.5 moles and the volume is equal to 1500 mL or 1.5L

Then, substituting into the equation, we have:

MolarConcentration=\frac{3.5moles}{1.5L}=2.33molar

Have a nice day!

7 0
2 years ago
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If a typical antacid tablet contains 2.0 g of sodium hydrogen carbonate, how many moles of carbon dioxide should one tablet yiel
ivolga24 [154]
The equation of the chemical reaction is NaHCO3 + H+ --> H2O + CO2 + Na
To determine the total number of moles of carbon dioxide, the given mass of sodium hydrogen carbonate is divided with its own molar mass. Then it is multiplied with the ratio between NaHCO3 and carbon dioxide. The total number of moles of CO2 one tablet should yield is 0.024 mole.
6 0
2 years ago
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