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-Dominant- [34]
2 years ago
14

Describe the pattern of the lewis dot structure of the first 18 elements

Chemistry
1 answer:
posledela2 years ago
6 0

Explanation: Lewis dot structures are the structures which represent the valence electrons of an atom. The dots in the structure are considered as the valence electrons.

First 18 elements of the periodic table are Hydrogen(H), Helium (He), Lithium (Li), Beryllium (Be), Boron (B), Carbon (C), Nitrogen (N), Oxygen (O), Fluorine (F), Neon(Ne), Sodium (Na), Magnesium (Mg), Aluminium (Al), Silicon (Si), Phosphorous (P), Sulfur (S), Chlorine (Cl) and Argon(Ar).

The valence electrons are the electrons which are present in the outermost shell of an atom. The electronic configuration of the elements are:

Hydrogen (H) = 1s^1 ; Valence electrons = 1

Helium (He) = 1s^2 ; Valence electrons = 2

Lithium (Li) = 1s^22s^1 ; Valence electrons = 1

Beryllium (Be) = 1s^22s^2 ; Valence electrons = 2

Boron (B) = 1s^22s^22p^1 ; Valence electrons = 3

Carbon (C) = 1s^22s^22p^2 ; Valence electrons = 4

Nitrogen (N) = 1s^22s^22p^3 ; Valence electrons = 5

Oxygen (O) = 1s^22s^22p^4 ; Valence electrons = 6

Fluorine (F) = 1s^22s^22p^5 ; Valence electrons = 7

Neon (Ne) = 1s^22s^22p^6 ; Valence electrons = 8

Sodium (Na) = 1s^22s^22p^63s^1 ; Valence electrons = 1

Magnesium (Mg) = 1s^22s^22p^63s^2 ; Valence electrons = 2

Aluminium (Al) = 1s^22s^22p^63s^23p^1 ; Valence electrons = 3

Silicon (Si) = 1s^22s^22p^63s^23p^2 ; Valence electrons = 4

Phosphorous (P) = 1s^22s^22p^63s^23p^3 ; Valence electrons = 5

Sulfur (S) = 1s^22s^22p^63s^23p^4 ; Valence electrons = 6

Chlorine(Cl) = 1s^22s^22p^63s^23p^5 ; Valence electrons = 7

Argon (Ar) = 1s^22s^22p^63s^23p^6 ; Valence electrons = 8

  • Elements hydrogen and helium belong to period 1 of the period table, so the lewis dot structures will have maximum of 2 electrons
  • Elements from lithium to neon belong to period 2 and the lewis dot structures will have maximum of 8 electrons.
  • Elements from sodium and argon belong to the period 3 of the periodic table, and will have maximum of 8 electrons in their lewis dot structures.

Lewis dot structures are attached below.

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Calculate the specific heat capacity for a 22.7-g sample of lead that absorbs 237 J when its temperature increases from 29.8 °C
soldier1979 [14.2K]

Answer:

\boxed {\boxed {\sf c\approx 0.159 \ J/ g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

c= \frac{Q}{m \times \Delta T}

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases <em>from</em> 29.8 °C <em>to </em>95.6 °C.

  • ΔT = final temperature -inital temperature
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Now we know all three variables and can substitute them into the formula.

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c= \frac {237 \ J}{22.7 \ g  \ \times  \ 65.8 \textdegree C}

Solve the denominator.

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c= \frac {237 \  J}{1493.66 \ g \textdegree C}

Divide.

c= 0.1586706479 J /g \textdegree C

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

c \approx 0.159 \ J/g \textdegree C

The specific heat capacity of lead is approximately <u>0.159 Joules per gram degree Celsius.</u>

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