Answer:
C)
f(–3) = 9
Step-by-step explanation:
Given f(x) = 4x^4 + 5x^3 – 15x^2 – 45
f(-3) means let x = -3
f(-3) = 4(-3)^4 +5(-3)^3 – 15(-3)^2 – 45
=4(81) +5(-27) -15(9) -45
= 324 - 135 - 135 -45
=9
We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.
To solve our given problem, we will divide total volume of wax by volume of one candle.
Volume of each candle will be equal to volume of sphere.
, where r represents radius of sphere.
We know that radius is half the diameter, so radius of each candle will be
cm.



Now we will divide 70,650 cubic cm of wax by volume of one candle.



Therefore, 40 candles can be made from 70,650 cubic cm of wax.
Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.
d/dx (2 x^2 y + y = 2x + 13)
4xy + 2x^2 y' + y' = 2
4xy + y'(2x^2 + 1) = 2
y' = (2- 4xy)/(2x^2 +1)
<span>ow we can use this in a linear equation for a slope
Ty = -5x/8 +5(3)/8 +8/8
= -5x/8 +(15+8)/8
= -5x/8 +23/8
this will gives us an approximation at x=2.8 now</span>
Answer:26
Step-by-step explanation:
Y=1.25^x-2/5-10
Take log of both sides
So Y+10=1.25^x-2/5
So log to base 10 of the two sides of the equation is
Log(Y+10)=X-2/5log1.25.
To make X the subject, divide both sides by log1.25.
Log(Y+10)/log1.25=X-2/5.
Recall that Y was given to be 115
It becomes log(115 +10)/Log1.25=x-0.4
21.64=x-0.4
X=25.6