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Veronika [31]
2 years ago
11

Given: Angle1 is complementary to Angle2. Angle2 is complementary to Angle3. Prove: mAngle1 = mAngle3 3 separate angles are show

n. The angles are labeled 1, 2, 3 from left to right. A 2-column table with 7 rows. Column 1 is labeled statements with the entries angle 1 is complementary to angle 2, angle 2 is complementary to angle 3, question mark, measure of angle 1 = 90 degrees minus measure of angle 2, measure of angle 2 + measure of angle 3 = 90 degrees, measure of angle 3 = 90 degrees minus measure of angle 2, measure of angle 1 = measure of angle 3. Column 2 is labeled reasons with the entries given, given, definition of complementary angles, subtraction equality property, definition of complementary angles, subtraction equality property, transitive property. What is the missing statement in step 3 of the proof? mAngle1 = mAngle2 mAngle1 + mAngle2 = 90° mAngle2 = mAngle3 mAngle2 + mAngle3 = 180°
Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0

Answer:

B: mAngle1 + mAngle2 = 90°

Step-by-step explanation:

Just took the test :D

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Given f(x) = 4x4 + 5x3 – 15x2 – 45, find f(–3).
poizon [28]

Answer:

C)  

f(–3) = 9

Step-by-step explanation:

Given f(x) = 4x^4 + 5x^3 – 15x^2 – 45

f(-3) means let x = -3

f(-3) = 4(-3)^4 +5(-3)^3 – 15(-3)^2 – 45

       =4(81) +5(-27) -15(9) -45

        = 324 - 135 - 135 -45

           =9

6 0
2 years ago
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A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If
jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

V=\frac{4}{3}\pi r^3, where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3

\text{Volume of one candle}=1766.25\text{ cm}^3

Now we will divide 70,650 cubic cm of wax by volume of one candle.

\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}

\text{Number of candles}=\frac{70,650}{1766.25}

\text{Number of candles}=40

Therefore, 40 candles can be made from 70,650 cubic cm of wax.

8 0
2 years ago
An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
The following curve passes through (3,1). Use the local linearization of the curve to find the approximate value of y at x=2.8.
Artist 52 [7]

d/dx (2 x^2 y + y = 2x + 13) 4xy + 2x^2 y' + y' = 2 4xy + y'(2x^2 + 1) = 2 y' = (2- 4xy)/(2x^2 +1)

<span>ow we can use this in a linear equation for a slope Ty = -5x/8 +5(3)/8 +8/8 = -5x/8 +(15+8)/8 = -5x/8 +23/8 this will gives us an approximation at x=2.8 now</span>

3 0
2 years ago
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The exponential functions y=(1-25)^x-2/5. -10 is shown hraphed along woth the horizontal line y=115 their intersection is (a,115
evablogger [386]

Answer:26

Step-by-step explanation:

Y=1.25^x-2/5-10

Take log of both sides

So Y+10=1.25^x-2/5

So log to base 10 of the two sides of the equation is

Log(Y+10)=X-2/5log1.25.

To make X the subject, divide both sides by log1.25.

Log(Y+10)/log1.25=X-2/5.

Recall that Y was given to be 115

It becomes log(115 +10)/Log1.25=x-0.4

21.64=x-0.4

X=25.6

3 0
2 years ago
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