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Scorpion4ik [409]
2 years ago
8

The Community Relief Fund receives a large donation of $2800. The foundation agrees to spend the money on $20 school bags, $25 s

weaters, $5 books. They want to buy 200 items and send them to schools in earthquake-hit areas. They must order as many books as school bags and sweaters combined.
Mathematics
1 answer:
asambeis [7]2 years ago
7 0

The question is incomplete:

The Community Relief Fund receives a large donation of $2800. The foundation agrees to spend the money on $20 school bags, $25 sweaters, $5 books. They want to buy 200 items and send them to schools in earthquake-hit areas. They must order as many books as school bags and sweaters combined. How many of each item should they order?

Answer:

They must order 40 bags, 60 sweaters and 100 books.

Step-by-step explanation:

From the information provided, you can write the following equations:

x+y+z=200 (1)

20x+25y+5z=2800 (2)

z=x+y (3), where:

x=amount of bags

y=amount of sweaters

z=amount of books

Now, you can replace (3) in (1) and (2):

x+y+x+y=200

2x+2y=200 (4)

20x+25y+5(x+y)=2800

20x+25y+5x+5y=2800

25x+30y=2800 (5)

Then, you will have 2 equations:

2x+2y=200 (4)

25x+30y=2800 (5)

You can isolate x in (4):

2x=200-2y

x=100-y (6)

After this, you can replace (6) in (5):

25(100-y)+30y=2800

2500-25y+30y=2800

5y=2800-2500

y=300/5

y=60

Next, you can replace the value of y in (6) to find the value of x:

x=100-60

x=40

Finally, you can replace the value of x and y in (3) to find the value of z:

z=40+60

z=100

According to this, the answer is that they must order 40 bags, 60 sweaters and 100 books.

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A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3
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Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

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The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

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(x - 3) = √8

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x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

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