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Degger [83]
2 years ago
10

A school fundraiser sells 1,200 raffle tickets. Each ticket costs $2. There is one grand prize worth $100 and 5 smaller prizes w

orth $20 each. What is the expected gain or loss for buying 1 ticket? loss of $1.91 loss of $1.83 gain of $2.16 loss of $1.99
Mathematics
1 answer:
tekilochka [14]2 years ago
4 0

Answer:

  loss of $1.83

Step-by-step explanation:

The average prize per ticket is ...

 ($100 +5($20))/1200 = $200/1200 ≈ $0.1667 ≈ $.17

You pay $2.00 for a ticket, so your expected value is ...

  -$2.00 +0.17 = -$1.83 . . . . a loss of $1.83

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A bag of trail mix weighs 1.625 pounds round 1.625 to the nearest hundredths
Andrew [12]
If you round 1.625 pounds to nearest hundredths its 1.63 pounds.
7 0
2 years ago
Evaluate the expression 2.1 + (–3.7h) + 1.9h – 1.4
zubka84 [21]
2.1 + (-3.7h) + 1.9h - 1.4
2.1 - 3.7h + 1.9h - 1.4
2.1 - 1.8h - 1.4
0.7 - 1.8h

the simplified form is 0.7 - 1.8h
5 0
2 years ago
An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by
GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis H_0 : \mu_1 - \mu_2 >2,

and the alternative hypothesis H_1: \mu_1 - \mu_2 \leq 2.

We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

s_p^2 = \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2} = 20.05,

where n_1 = 12, n_2 =10, s_1 =4, s_2 = 5.

The mean of material 1 and material 2 are \mu_1 =85, \mu_2=81 respectively and mean difference d is equal to 4. The hypothesize difference d_0 is equal to 2.

To find the T-score, we use the following formula

T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}

Substituting all the values into the T-score formula gives us T = 1.04, and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

6 0
2 years ago
A news organization previously stated that three of four people believed that the state of the economy was the country's most si
gizmo_the_mogwai [7]

Answer:

Option d)

H_{0}: p = 0.75\\H_A: p \neq 0.75

Step-by-step explanation:

We are given the following in the question:

Three of four people believed that the state of the economy was the country's most significant concern.

They would like to test the new data against this prior belief.

The null hypothesis will state that the three of four people believed that the state of the economy was the country's most significant concern.

The alternate hypothesis will state that this is not true. It states that people believed that the state of the economy was the country's most significant concern is not the same.

p =\dfrac{3}{4} = 0.75

We design the null and the alternate hypothesis  

H_{0}: p = 0.75\\H_A: p \neq 0.75

4 0
2 years ago
a car travels 30 1/2 miles in 2/3 of an hour. what is the average speed, in miles per hour, of the car ?
Contact [7]

Answer:

speed=225.75 miles per hour

Step-by-step explanation:

given:

s=301/2

t=2/3

we have,

v=s/t

v=(301/2)/(2/3)

=(301/2)×3/2

=903/4

v=225.75

therefore, speed of car will be 225.75 miles per hour

6 0
1 year ago
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