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mel-nik [20]
1 year ago
15

Michael needs to pay car insurance premiums of $958 two times per year. He has decided to make deposits from each paycheck to a

savings account for “Other Expenses (Predictable)” to cover this expense. How much should Michael deposit from each paycheck if the paycheck is bi-weekly?
a.
$80
b.
$74
c.
$160
d.
$37
Mathematics
2 answers:
nata0808 [166]1 year ago
8 0

Given: Car insurance premium in a first half year = $958

Car insurance premium in the second half year = $958

Total Car insurance premium in year = 2 × $958 = $ 1916

Nature of paid premium is bi-weekly = in 2 weeks

There are total 52 weeks in a year.

So, the total number of bi-week = 26

Total deposited amount per bi-weekly = $ 1916 ÷ 26 =$ 73.69 ≈ $ 74

Hence, the required amount bi-weekly will be $ 74. Therefore, option b. $ 74 is the correct option.


mash [69]1 year ago
7 0

Answer:

The correct Option is B. $74

Step-by-step explanation:

Car insurance which is to be paid two times a year = $958

∴ Car insurance premium paid in first half of the year  = $958

and Car insurance premium in the second half of the  year = $958

Total Car insurance premium paid in one year = 2 × $958 = $ 1916

It is given that the Premium is to be paid bi-weekly

⇒ In two weeks the premium is paid once

Now, There are total 52 weeks in a year.

\text{So, the total number of bi weeks = }\frac{52}{2}=26\text{ weeks}\\\\\text{Total deposited amount per bi weekly = }\frac{1916}{26}=73.69\approx \$74

Hence, the required amount of premium to be paid bi-weekly will be $ 74. Therefore, The correct Option is B. $74

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Answer:

No

Step-by-step explanation:

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5 0
2 years ago
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tensa zangetsu [6.8K]

Answer:

He should combine 1 kg of 30% alloy and 3 kg of 10% alloy.

Step-by-step explanation:

Let x = mass of 30% ally.

Let y = mass of 10% alloy.

He needs 4 kg of alloy, so the first equation, dealing with masses, is

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Now we deal with the amount of gold.

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He uses y mass of 10% gold alloy. The amount of gold in that mass is 0.1y.

The total mass of gold is 0.3x + 0.1y. We are told the told the end alloy is 4 kg of 15% gold alloy. That contains 0.15(4) kg = 0.6 kg of gold.

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Now we put together the two equations as a system of equations.

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Multiply both sides of the second equation by -10.

-3x - y = -6

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---------------------

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6 0
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Answer:

p=7x

Step-by-step explanation:

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This equation is in the form a^[2]x + bx + c.

<u><em>The 'c' is common for both equations, this means the 'a' and 'b' must also be common. </em></u>

There are two ways to find p: 'a' or 'b'

<u>a method</u>

49x^[2] = p^[2]

=> The square root of both sides = 7x = p

<u>b method</u>

28x = 4p

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</span>
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