A. archaea because lack a nucleus and cell organelles ·cell walls do not contain peptidoglycan
Answer:
When two objects are near each other, increasing one object's mass would cause the gravitational force of the object to increase. where m and M are the masses of the two objects, d is the distance between their centres, and G is the gravitational constant.
Explanation:
one is big one is small
It is like when you take a medicine you don't need, it becomes useless when you need it because your body can fight it off. So, I would have to say that the pesticides have been used on the bugs so much that they can finally fight it off. I really hoped I helped :D
Answer: It proposes that the entire double‑stranded DNA molecule serves as a template for a whole new molecule of DNA.
Explanation:
In semi-conservative DNA replication:
- a parent double-stranded DNA splits in two.
- Each strand serves as template, and then read by the enzyme, DNA polymerase, to ensure accurate synthesis of a new daughter strand for both
- the newly synthesized strand contains nucleotides that are complimentary to free nucleotides present in the parent strand.
Thus, because the parent double strand is retained in the newly synthesized DNA, this model is described as semi-conservative
Answer:
0.2404
Explanation:
The genes R/r and E/e are linked and there is 4% recombination between them.
<u>The possible genotypes and phenotypes are:</u>
- RR or Rr: Rh+ blood type
- rr: Rh- blood type
- EE or Ee: elliptocytosis
- ee: normal red blood cells
Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).
Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele from his father, so he has the genotype eR/Er.
Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome <em>er </em>from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.
The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).
<u />
<u>Tom will produce the following gametes:</u>
- eR, parental (0.48)
- Er, parental (0.48)
- er, recombinant (0.02)
- ER (recombinant (0.02)
<u>Terri will produce the following gametes:</u>
- ER, parental (0.48)
- er, parental (0.48)
- Er, recombinant (0.02)
- eR, recombinant (0.02)
A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:
- Er (0.48) × er (0.48) = 0.2304 Er/er
- Er (0.48) × Er (0.02) = 0.0096 Er/Er
- er (0.02) × Er (0.02) = 0.0004 er/Er
And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404
